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Ann [662]
3 years ago
11

Stephanie has a homeowners insurance policy for her $355,000 home with an annual premium of $0.42 per $100 of value and a deduct

ible of $500. Under this policy, in the event of a major mishap, Stephanie would have a total annual out-of-pocket expense of [($355,000/100) x $0.42] + $500 = $1,991
Stephanie would like to lower her premium by increasing her deductible. If Stephanie wants to increase her deductible to $1000, what annual premium would result in an annual out-of-pocket expense that is about the same as her current plan?
a. $0.16 per $100 of value
b. $0.28 per $100 of value
c. $0.35 per $100 of value
d. $0.46 per $100 of value\
Mathematics
1 answer:
frosja888 [35]3 years ago
5 0

Answer:

$0.28 per 100 of value (B)

Step-by-step explanation:

Stephanie has a homeowner insurance policy of $355,000

Annual premium = $0.42 per 100

There is a deductible of $500

Stephanie has an annual out of pocket expense of

[($355,000/100) x $0.42] + $500 = $1,991

From the question, Stephanie now wants a new deductible amount of 1000.

Let X be the new annual premium

[(355,000X) / 100] + 1000 = 1991

3550X + 1000 = 1991

3550X = 1991 -1000

3550X = 991

X = 991/3550

X = 0.2791

X = 0.28 ( approximately)

The new annual premium is $0.28 per 100 of value

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36 / [10 - (3-1)²]

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Next, we should still simplify what is inside the parentheses but continue to solve the exponents (the next letter in PEMDAS).

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After that, we should compute the subtraction that is inside the parentheses.

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Finally, we can solve using division.

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Now, we can move onto problem 20:

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To solve this problem, we need to use the distributive property, which allows us to distribute the coefficient of 1/4 through the parentheses by multiplying each term by 1/4.

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Therefore, your answer to problem 19 is 6 and the answer to problem 20 is 4d -6.

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2 years ago
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Ierofanga [76]

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Step-by-step explanation:

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3 years ago
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sleet_krkn [62]

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