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Ann [662]
3 years ago
11

Stephanie has a homeowners insurance policy for her $355,000 home with an annual premium of $0.42 per $100 of value and a deduct

ible of $500. Under this policy, in the event of a major mishap, Stephanie would have a total annual out-of-pocket expense of [($355,000/100) x $0.42] + $500 = $1,991
Stephanie would like to lower her premium by increasing her deductible. If Stephanie wants to increase her deductible to $1000, what annual premium would result in an annual out-of-pocket expense that is about the same as her current plan?
a. $0.16 per $100 of value
b. $0.28 per $100 of value
c. $0.35 per $100 of value
d. $0.46 per $100 of value\
Mathematics
1 answer:
frosja888 [35]3 years ago
5 0

Answer:

$0.28 per 100 of value (B)

Step-by-step explanation:

Stephanie has a homeowner insurance policy of $355,000

Annual premium = $0.42 per 100

There is a deductible of $500

Stephanie has an annual out of pocket expense of

[($355,000/100) x $0.42] + $500 = $1,991

From the question, Stephanie now wants a new deductible amount of 1000.

Let X be the new annual premium

[(355,000X) / 100] + 1000 = 1991

3550X + 1000 = 1991

3550X = 1991 -1000

3550X = 991

X = 991/3550

X = 0.2791

X = 0.28 ( approximately)

The new annual premium is $0.28 per 100 of value

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Answer:

Option 1, 2 and 4

Step-by-step explanation:

3x-4y-8= 12

3x-4y= 12+8 (bring constants to 1 side)

3x-4y= 20 (simplify)

For a point to be a solution of the above equation, substitute the x and y coordinates into 3x-4y and see if it equals to 20.

Option 1: (0, -5)

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This is correct

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3(4)-4(-2)=20

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3) (8,2)

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This is incorrect.

4) (-16, -17)

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5) (-1, -8)

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3 years ago
The graph of the quadratic function y = ax^2 + bx + c is given.<br> Find a + b + c.
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Answer:

\frac{145}{24}\approx 6***

Answers may vary depending on the person reading the graph.

It is hard to tell what they think crosses nicely.

For example, I decided that the graph crossed nicely at the following points:

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(2,8)

(6,5)

Step-by-step explanation:

I see that the graph crosses at (0,3),(2,8), and (6,5).

The equation y=ax^2+bx+c tells us the y-intercept is c since when x=0 we have y=a(0)^2+b(0)+c=0+0+c=c.

The y-intercept for our graph is 3. Therefore, c=3.

So far we have the equation:

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Let's enter the other points creating a system of linear equations to solve:

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