This is because 3 3/4 (3.75) + 1 1/2 (1.50) is 5.25. So first you can find the common denominator for 3/4 and 1/2. The xommon denominator is 4 since 3/4 already have a common denominator of 4 you leave 3 34 alone. For 1/2 multiply the nuerator and denominator by 2 resulting in 2/4 so together its 1 2/4. When you add 3 3/4+ 1 2/4, you will get 5 1/4 or 5.25. The easier way is just converting the fractions to decimal. Therefore the answer is 5.25. 5.25> 5
Answer: figure C.
Explanation:
The HL theorem is the hypotenuse leg theorem.
The HL theorem is referred to the congruency of right triangles.
This theorem states that two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles.
Figure A shows the congruency of two pairs of legs. So, this is not the answer.
Figure B shows the congruency of one pair of legs and one pair of angles. So, this is not the answer.
Figure C. shows the congruency of the two hypotenuses and one pair of legs. So, this is the righ answer.
A can of paint is a cylinder, so we must use the surface area for a cylinder.
2(

r

) is the top and bottom.
The surface of the can is a rectangle with a length equal to the circumference of the can.

<h2>Given :- </h2><h2 />
- Side of the square field = 70m
- Length of the rectangular field = 90m
- Breadth of the rectangular field = 60m
<h2>To Find :-</h2>
- Perimeter of the square field
- Perimeter of the rectangular field
<h2>Solution :-</h2>
Perimeter of the square = 4 × side
By substituting values,
⇒ 4 × 70m
➥ 280m
<h3><u>Hence, </u><u>Faliha</u><u> runs 280m around a Square </u><u>field</u></h3>
Perimeter of the rectangle = 2( length + Breadth)
By substituting values,
⇒ 2( 90m + 60m )
⇒ 2( 150m)
➥ 300m
<h3><u>Hence, Rameen runs 300m around a rectangular field</u></h3>
By comparing perimeters, Rameen runs more than Faliha
Distance runs more by rameen = Distance covered by rameen - distance covered by faliha
By substituting values,
⇒ 300m - 280m
➠ 20m
<h3><u>Hence, </u><u>Rameen</u><u> runs more around a rectangular field by 20</u><u>m</u></h3>
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