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2 years ago

Solve for p : p-4 -136 p=

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

6 0

Answer:

The answer is P = 40

if you click the image it will show you how to solve the equation. I hope this helps you :)

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Thee vertex of a parabola is (-5,2), and its focus is (-1,2). What is the standard form of the parabola?

Alla [95]

Check the picture below. So the parabola looks more or less like so.

$\bf \textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf \begin{cases} h=-5\\ k=2\\ p=4 \end{cases}\implies 4(4)[x-(-5)]=[y-2]^2\implies 16(x+5)=(y-2)^2 \\\\\\ x+5=\cfrac{1}{16}(y-2)^2\implies x = \cfrac{1}{16}(y-2)^2-5$

6 0

2 years ago

Read 2 more answers

Subtract. Write the difference in simplest form. (5n - 3) - (-2n + 7)

kolezko [41]

Answer:

Simplifying

(5n + -3) + -1(-2n + 7) = 0

Reorder the terms:

(-3 + 5n) + -1(-2n + 7) = 0

Remove parenthesis around (-3 + 5n)

-3 + 5n + -1(-2n + 7) = 0

Reorder the terms:

-3 + 5n + -1(7 + -2n) = 0

-3 + 5n + (7 * -1 + -2n * -1) = 0

-3 + 5n + (-7 + 2n) = 0

Reorder the terms:

-3 + -7 + 5n + 2n = 0

Combine like terms: -3 + -7 = -10

-10 + 5n + 2n = 0

Combine like terms: 5n + 2n = 7n

-10 + 7n = 0

Solving

-10 + 7n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '10' to each side of the equation.

-10 + 10 + 7n = 0 + 10

Combine like terms: -10 + 10 = 0

0 + 7n = 0 + 10

7n = 0 + 10

Combine like terms: 0 + 10 = 10

7n = 10

Divide each side by '7'.

n = 1.428571429

Simplifying

n = 1.428571429

3 0

2 years ago

Simplify the expression. (the quantity x to the one-sixth power end quantity to the power of 3.)

Usimov [2.4K]

Answer:

$\sqrt{x}$

Step-by-step explanation:

If we have that worded expression, we can convert it into actual mathematical terms.

x to the one sixth power: $x^{\frac{1}{6}}$

That to the power of 3:

$(x^{\frac{1}{6}})^3$

Using exponent rules, since we have a power to a power, the powers multiply, so:

$x^{\frac{1}{6}\cdot 3}\\\\x^{\frac{3}{6}}\\\\ x^{\frac{1}{2}}$

If we have a number to a fraction power, the denominator becomes the “find the (denominator) root of x.

So:

$x^{\frac{1}{2}} = \sqrt{x}$

Hope this helped!

8 0

2 years ago

Read 2 more answers

A certain article indicates that in a sample of 1,000 dog owners, 610 said that they take more pictures of their dog than of the

lbvjy [14]

Answer:

(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).

(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).

(c) First, the confidence level in part(b) is more than the confidence level in part(a) is, so the critical value of part(b) is more than the critical value of part(a), Second the margin of error in part(b) is more than than in part(a).

Step-by-step explanation:

(a)

Let X = number of dog owners who take more pictures of their dog than of their significant others or friends.

Given:

X = 610

n = 1000

Confidence level = 90%

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The sample proportion is:

$\hat p=\frac{X}{n}=\frac{610}{1000}=0.61$

The critical value of z for a 90% confidence level is:

$z_{\alpha/2}=z_{0.10/2}=z_[0.05}=1.645$

Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.61\pm 1.645\sqrt{\frac{0.61(1-0.61}{1000}}\\=0.61\pm 0.015\\=(0.595, 0.625)\\\approx(0.60, 0.63)$

Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).

Interpretation:

There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).

Correct option is (3).

(b)

Let X = number of dog owners who are more likely to complain to their dog than to a friend.

Given:

X = 440

n = 1000

Confidence level = 95%

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The sample proportion is:

$\hat p=\frac{X}{n}=\frac{440}{1000}=0.44$

The critical value of z for a 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.44\pm 1.96\sqrt{\frac{0.44(1-0.44}{1000}}\\=0.44\pm 0.016\\=(0.424, 0.456)\\\approx(0.42, 0.46)$

Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend is (0.42, 0.46).

Interpretation:

There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).

Correct option is (1).

(c)

The confidence interval in part (b) is wider than the confidence interval in part (a).

The width of the interval is affected by:

The confidence level
Sample size
Standard deviation.

The confidence level in part (b) is more than that in part (a).

Because of this the critical value of z in part (b) is more than that in part (a).

Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.

First, the confidence level in part(b) is more than the confidence level in part(a) is, so the critical value of part(b) is more than the critical value of part(a), Second the margin of error in part(b) is more than than in part(a).

4 0

2 years ago

If the 10th of the 10 consecutive numbers is 10, what is their sum?

liq [111]

Represent these consecutive numbers (assuming that they are all integers):

x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.

Think of it this way: there are 10 consecutive numbers, and the last one is 10.

Working backwards, we get the sequence 10, 9, ... 3, 2, 1.

The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:

sum here = 10(1+10)/2 = 5(11) = 55 (answer)

7 0

2 years ago