Can someone please help e with this question

Two friends Ana and Juan are buying books by joining the History Book

Travka [436]

Answer:

Ana spent $17 per book on average.

Juan spent $14.78 per book on average.

y = $15 + 17x--------- equation 1

y= $10 + 14.78 x------------- equation 2

Step-by-step explanation:

Ana has to pay a yearly fee of $15 to join.

She spends a total of $525 for 30 books.

The amount spent on books = Total amount - yearly fee

= $525- $15= $510

Price per book on the average = $510/30= $ 17

Ana spent $17 per book on average.

Juan has to pay a yearly fee of $10 to join.

He spends a total of $350 for 23 books.

The amount spent on books = Total amount - yearly fee

= $350- $10= $340

Price per book on the average = $340/23= $ 14.78≅ $15

Juan spent $14.78 per book on average.

The function can be established if y gives the total cost and x gives the number of books

y = $15 + 17x--------- equation 1

y= $10 + 14.78 x------------- equation 2

Juan has a better deal because the yearly fee is less also the price per book is less.

8 0

2 years ago

What is the distance between 16 and -25

murzikaleks [220]

the distance between 16 and -25 is 41

4 0

2 years ago

Find the greatest number that divides451, 328 and 673 leaving 1, 4 and 1,respectively as remainders.

Vesna [10]

You're looking for the largest number x such that

x ≡ 1 (mod 451)

x ≡ 4 (mod 328)

x ≡ 1 (mod 673)

Recall that

x ≡ a (mod m)

x ≡ b (mod n)

is solvable only when a ≡ b (mod gcd(m, n)). But this is not the case here; with m = 451 and n = 328, we have gcd(m, n) = 41, and clearly

1 ≡ 4 (mod 41)

is not true.

So there is no such number.

4 0

2 years ago

Forgot to do this over winter break. Its due tomorrow and I haven't used my brain for 2 weeks. HELPPP (may have to zoom in)

ANEK [815]

1. 60,30,90 right triangle. y will be hypotenuse/2, x will be
hypotenuse*sqrt(3)/2. So x = 16*sqrt(3)/2 = 8*sqrt(3), approximately 13.85640646
y = 16/2 = 8
2. 45,45,90 right triangle (2 legs are equal length and you have a right angle).
X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8
3. Just a right triangle with both legs of known length. Use the Pythagorean theorem
x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13
4. Another right triangle with 1 leg and the hypotenuse known. Pythagorean theorem again.
y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374
6. Another 45,45,90 triangle with the hypotenuse known. Both unknown legs will have the same length. And Pythagorean theorem will be helpful.
x = y.
12^2 = x^2 + y^2
12^2 = x^2 + x^2
12^2 = 2x^2
144 = 2x^2
72 = x^2
sqrt(72) = x
6*sqrt(2) = x
x is approximately 8.485281374
7. A 30,60,90 right triangle with the short leg known. The hypotenuse will be twice the length of the short leg and the remaining leg can be determined using the Pythagorean theorem.
y = 11*2 = 22.
x = sqrt(22^2 - 11^2) = sqrt(484 - 121) = sqrt(363) = sqrt(121 * 3) = 11*sqrt(3). Approximately 19.05255888
8. A 30,60,90 right triangle with long leg known. Can either have fact that in that triangle, the legs have the ratio of 1:sqrt(3):2, or you can use the Pythagorean theorem. In this case, I'll use the 1:2 ratio between the unknown leg and the hypotenuse along with the Pythagorean theorem.
x = 2y
y^2 = x^2 - (22.5*sqrt(3))^2
y^2 = (2y)^2 - (22.5*sqrt(3))^2
y^2 = 4y^2 - 1518.75
-3y^2 = - 1518.75
y^2 = 506.25 = 2025/4
y = sqrt(2025/4) = sqrt(2025)/sqrt(4) = 45/2
Therefore:
y = 22.5
x = 2*y = 2*22.5 = 45
9. Just a generic right triangle with 2 known legs. Use the Pythagorean theorem.
x = sqrt(16^2 + 30^2) = sqrt(256 + 900) = sqrt(1156) = 34
10. Another right triangle, another use of the Pythagorean theorem.
x = sqrt(50^2 - 14^2) = sqrt(2500 - 196) = sqrt(2304) = 48

8 0

3 years ago

Using a white-board with graph paper or graphing technology such as Geogebra be able to perform a reflection for a pre-image ove

Marta_Voda [28]

Explanation:

The line of reflection is the perpendicular bisector of the segment joining a point with its reflected image.

___

The segment joining a point with its reflection is as short as possible consistent with the requirement that the reflected point be the same distance from the line that the original is. That means it is perpendicular to the line of reflection. Since the distance from that line is the same on either side, the line of reflection bisects the joining segment.

7 0

2 years ago