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1 year ago

Home of points!!! ok get your

Mathematics

2 answers:

Korvikt [17]1 year ago

4 0

Answer:

Hi!

Explanation:

Hope your day is going well!

saul85 [17]1 year ago

3 0

Answer:

you have really really gone crazy

Step-by-step explanation:

no words

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2 years ago

Writing Trig Ratios.

notsponge [240]

Answer:

The ratios are as follows for the given angle:

sineX=opposite/hypotenuse

cosineX=adjacent/hypotenuse

tangentX=opposite/adjacent

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7.) sinZ=24/40

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2 years ago

Question (in need of help)

mr Goodwill [35]

<h3>Required Answer:-</h3>

This is an right angle ∆ and the side lengths containing a right angle are 9 and 11.

By Pythagoras theoram,

${p}^{2} + {b}^{2} = {h}^{2}$

where p is the perpendicular, b is the base and h is the hypotenuse.

Plugging the values,

${9}^{2} + {11}^{2} = {h}^{2}$

Then,

$h = \sqrt{ {9}^{2} + {11}^{2} }$

$h = 14.12(approx.)$

<h3>Hence:-</h3>

The x of the right angled ∆ = 14.12

6 0

2 years ago

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