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ioda
3 years ago
7

A multiple-channel queuing system with a Poisson arrival rate and exponential service time has an average arrival rate of four c

ustomers per hour and an average service time of 18 minutes per customer. The minimum number of servers required to avoid an overloaded system is
Business
1 answer:
12345 [234]3 years ago
6 0

Answer:

1.2

Explanation:

The computation of the minimum number of servers required to avoid an overloaded system is shown below:-

Average service time =  Average service time ÷ number of minutes in a hour

18 min = 18 ÷ 60 per hr

= 0.3 hr per customer

Now for four customers, it would be

min servers = 4 × 0.3

= 1.2

So, the correct answer is min servers = 2 as servers cant be in fractions

Therefore we have applied the above formula.

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