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ioda
3 years ago
7

A multiple-channel queuing system with a Poisson arrival rate and exponential service time has an average arrival rate of four c

ustomers per hour and an average service time of 18 minutes per customer. The minimum number of servers required to avoid an overloaded system is
Business
1 answer:
12345 [234]3 years ago
6 0

Answer:

1.2

Explanation:

The computation of the minimum number of servers required to avoid an overloaded system is shown below:-

Average service time =  Average service time ÷ number of minutes in a hour

18 min = 18 ÷ 60 per hr

= 0.3 hr per customer

Now for four customers, it would be

min servers = 4 × 0.3

= 1.2

So, the correct answer is min servers = 2 as servers cant be in fractions

Therefore we have applied the above formula.

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<em>B. Yes, because Larry did not follow safe work practices by rushing down the hall with the cart.</em>

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At least, the General Duty Clause of the OSH Act requires employers to provide safe work environments free from recognized present or future hazards.

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2 years ago
A(n) __________is a test where a candidate is put into a high-pressure situation in a controlled environment so that the danger
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3 years ago
The aggregate demand curve shows a ________ relationship between ________ and aggregate output ________.
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Why should i ever care just kidding 
6 0
3 years ago
which question or questions should you ask yourself when determining how much money you can afford to spend on a mortgage
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What is my income. then subtract
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3 0
3 years ago
Robert Gillman, an equity research analyst at Gillman Advisors, believes in efficient markets. He has been following the mining
taurus [48]

Answer:

Growth rate 2.4%

Explanation:

MV=D1/(Ke-g)

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D1=Dividend at year end=$.72

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By putting above values in formula, we get;

MV=D1/(Ke-g)

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4 0
3 years ago
Read 2 more answers
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