Question

5. You are driving with a friend who is sitting to your right on the passenger side of the front seat. You would like to be closer to your friend and decide to use your knowledge of physics to achieve your romantic goal. So you'll make a sharp turn. Which direction should you turn so as to make your friend slide closer to you? If the coefficient of static friction between your friend and the seat of the car is 0.40, and the radius of curvature of the turn is 100 m, what is the minimum speed (in mph) with which you could make your turn and still have your friend slide your way? On a wet road, the typical coefficient of static friction between your car tires and the road is about 0.40. What would happen if you tried this little stunt on a rainy day?

Answer 1

Answer:

(mu)r*g=v^2

Explanation:

Ok this is how I approached it: I know f= ma where a is acceleration, which is v^2/r I know static friction is f=(mu)N where N is m*g therefore: (mu)m*g=m*v^2/r m's cancel out leaving: (mu)r*g = v^2