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Gennadij [26K]
3 years ago
8

What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is 1

.75 m wide and 9.00 m below the top of the cliff?
Physics
1 answer:
kotegsom [21]3 years ago
3 0

Answer:

1.292 m/s

Explanation:

For her trajectory motion, the time taken to descend to a height of 9 m is given as

t = √(2H/g) = √[(2×9)/9.8] = 1.355 s

Then the range (horizontal distance covered) is related to the time to reach that height and the corresponding horizontal velocity as shown in

R = ut

where u = initial horizontal velocity

1.75 = u × 1.355

u = 1.292 m/s

This is the minimum speed just as she leaves the top of the cliff to miss the ledge described in the question.

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7 0
1 year ago
A coin with a diameter 3.00 cm rolls up a 30.0 inclined plane. The coin starts out with an initial angular speed of 60.0 rad/s
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This question is in complete.The question is

A coin with a diameter 3.00 cm rolls up a 30.0° inclined plane. The coin starts out with an initial angular speed of 60.0 rad/s and rolls in a straight line without slipping. If the moment of inertia of the coin is(1/2) MR² , how far will the coin roll up the inclined plane (length along the ramp)? Hint: Conservation of mechanical energy.

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