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Gennadij [26K]
3 years ago
8

What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is 1

.75 m wide and 9.00 m below the top of the cliff?
Physics
1 answer:
kotegsom [21]3 years ago
3 0

Answer:

1.292 m/s

Explanation:

For her trajectory motion, the time taken to descend to a height of 9 m is given as

t = √(2H/g) = √[(2×9)/9.8] = 1.355 s

Then the range (horizontal distance covered) is related to the time to reach that height and the corresponding horizontal velocity as shown in

R = ut

where u = initial horizontal velocity

1.75 = u × 1.355

u = 1.292 m/s

This is the minimum speed just as she leaves the top of the cliff to miss the ledge described in the question.

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A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of th
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Answer:

91.84 m/s²

Explanation:

velocity, v = 600 m/s

acceleration, a = 4 g = 4 x 9.8 = 39.2 m/s^2

Let the radius of the loop is r.

he experiences a centripetal force.

centripetal acceleration,

a = v² / r

39.2 x r = 600 x 600

r = 3600 / 39.2

r = 91.84 m/s²

Thus, the radius of the loop is 91.84 m/s².

8 0
3 years ago
When light is reflected by a mirror, the angle of incidence is always A. equal to the angle of reflection. B. less than the angl
ankoles [38]
When light is reflected by a mirror, the angle of incidence is always <span>A. equal to the angle of reflection. We know this by the Law of Reflection.</span>
6 0
3 years ago
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If the density of a substance is 5g/cm3 and the volume is 10cm3,<br> determine the mass.
vaieri [72.5K]

Answer:

(5g/cm³)*(10cm³) = 50g

Explanation:

This is just a conversion formula. Easy to find using dimensional analysis.

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6 0
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In addition to a reference point you also need distance and __________ to describe location
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displacement

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6 0
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The displacement vector A and B when added together , give the resultant vector R so that R= A+B use the data in the drawing and
Salsk061 [2.6K]
The addition of vectors involve both magnitude and direction. In this case, we make use of a triangle to visualize the problem. The length of two sides were given while the measure of the angle between the two sides can be derived. We then assign variables for each of the given quantities.

Let:

b = length of one side = 8 m
c = length of one side = 6 m
A = angle between b and c = 90°-25° = 75°

We then use the cosine law to find the length of the unknown side. The cosine law results to the formula: a^2 = b^2 + c^2 -2*b*c*cos(A). Substituting the values, we then have: a = sqrt[(8)^2 + (6)^2 -2(8)(6)cos(75°)]. Finally, we have a = 8.6691 m.

Next, we make use of the sine law to get the angle, B, which is opposite to the side B. The sine law results to the formula: sin(A)/a = sin(B)/b and consequently, sin(75)/8.6691 = sin(B)/8. We then get B = 63.0464°. However, the direction of the resultant vector is given by the angle Θ which is Θ = 90° - 63.0464° = 26.9536°.

In summary, the resultant vector has a magnitude of 8.6691 m and it makes an angle equal to 26.9536° with the x-axis.
 
5 0
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