Answer:
The velocity of the object at the bottom is, v = 17.15 m/s
Explanation:
Given data,
The initial velocity of the object, u = 0
The height of the hill, h = 15 m
Let 'S' be the distance of the slope of the hill and 'Ф' be the slope of the hill formed with the ground.
The acceleration due to gravity component along the slope is given by,
a = g Sin Ф
The distance of the slope since height 'h' of the hill is given,
s = h / Sin Ф
Using the III equation of motion,
v² = 2 as (∵ u = 0)
v² = 2 x g Sin Ф x h / Sin Ф
= 2 gh
Therefore,
<em> v = √(2gh)</em>
Substituting the given values,
v = √(2x9.8x15)
= 17.15 m/s
Hence, the velocity of the object at the bottom is, v = 17.15 m/s
That depends on my mass and the height of the ladder.
Answer:
option A
Explanation:
given,
distance between two masses is doubled
new distance, r' = 3 r
using gravitational force equation
............(1)
new gravitational force
now from the given condition
now, from equation (1)
now, the change in gravitational force factor is equal to 
Hence, the correct answer is option A
Answer:
h = 4.04 m
Explanation:
Given that,
Mass of a child, m = 25 kg
The speed of the child at the bottom of the swing is 8.9 m/s
We need to find the height in the air is the child is able to swing. Let the height is h. Using the conservation of energy such that,
Put all the values,
So, the child is able to go at a height of 4.04 m.
Speed can never be negative because it does not depend in which direction the car moves whereas, velocity will change if a car turns from due North to East.
Quantities which can be described only by their magnitudes are called scalars and those which are described by both, magnitude and direction are vectors
