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Flura [38]
4 years ago
6

What are equivalent equations? How do you find them? Write a few sentences describing them.

Mathematics
2 answers:
Tanya [424]4 years ago
7 0

Answer:

Equivalent equations have the same solution. You can create equivalent equations by performing the same operations on each side of the equation. You can check for equivalence by finding the solution for each equation.

hope this helps

ludmilkaskok [199]4 years ago
4 0

What are they?

They are like same answer solutions. Some describe them as being equal to each other.

How to solve:

Step1 - Check for distributive property on each side of the equal sign. If present, complete the distributive property. There is no distributive property in our example.  

Step 2 - Check for combining like terms on each side of the equal sign. If present, combine all like terms on the same sign of the equal sign. There are no like terms present in our example.  

Step 3 - Collect all the variables on the same side of the equal sign. Do this by adding or subtracting (whichever is opposite of the current operation) the variable with its coefficient from both sides of the equation. By subtracting 7.50x (Subtracting is opposite of a positive 7.50 x), we can move the x's on the same side of the equation (what you do to one side of the equation you must do to the other side to keep the equation equal.  

Step 4 - Collect all constants on the opposite side of the equation as the variable. Accomplish this by adding or subtracting (whichever is the opposite of the current operation) the constant from both sides of the equation. The 12 is a positive 12 so we do the opposite operation which would be subtracting 12. What you do to one side of the equation you must do to the other.  

Step 5 - Isolate the variable by multiplying or dividing the coefficient (whichever is opposite of the current operation) of the variable on both sides of the equation. At this point, you should have the variable equals a number. The variable is being multiplied by -1.50, so the opposite operation is to divide by -1.50. This has to be done to both sides to keep the problem equal.

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Occasionally a savings account may actually pay interest compounded continuously. For each deposit, find the interest earned if
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1. Occasionally a savings account may actually pay interest compounded continuously. For each​ deposit, find the interest earned if interest is compounded​ (a) semiannually,​ (b) quarterly,​ (c) monthly,​ (d) daily, and​ (e) continuously. Use 1 year = 365 days.

Principal ​$1031

Rate 1.4%

Time 3 years

Answer:

a) $ 44.07

b) $ 44.15

c) $ 44.20

d) $ 44.22

e) $ 44.22

Step-by-step explanation:

The formula to find the total amount earned using compound interest is given as:

A = P(1 + r/n)^nt

Where A = Total amount earned after time t

P = Principal = $1031

r = Interest rate = 1.4%

n = compounding frequency

t = Time in years = 3 years

For each​ deposit, find the interest earned if interest is compounded

(a) semiannually

This means the interest is compounded 2 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/2) ^2 × 3

A = 1031 (1 + 0.007)^6

A = $ 1,075.07

A = P + I where

I = A - P

I = $1075.07 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.07

​(b) quarterly

This means the interest is compounded 4 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/4) ^4 × 3

A = 1031 (1 + 0.014/4)^12

A = $ 1,075.15

I = A - P

I = $1075.15 - $1031

A = P + I where

P (principal) = $ 1,031.00

I (interest) = $ 44.15

(c) monthly,

​ This means the interest is compounded 12 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/12) ^12 × 3

A = 1031 (1 + 0.014/12)^36

A = $ 1,075.20

A = P + I where

I = A - P

I = $1075.20 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.20

(d) daily,Use 1 year = 365 days

This means the interest is compounded 365 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/365) ^2 × 3

A = 1031 (1 + 0.00365)^365 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

(e) continuously. .

This means the interest is compounded 2 times in a year

Hence:

A = Pe^rt

A = 1031 × e ^0.014 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

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3 years ago
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