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nataly862011 [7]
3 years ago
14

Complete the table shown to the right for the population

Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0

Answer:

2,1

Step-by-step explanation:

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-1/2 because slope is the rise over the run. If you count on the grid from one point on the line to another you go up one and 2 to the left meaning the slope is 1/2, buttttt when the line decreases going to the right, it has a negative slope so you just add a - sign in front
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Arrange the pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (20, 40)
gavmur [86]

Answer: m1 = 0.5

M2= 0.375

M3 = 2.25

M4 = 3.0

M5 = 13.5

M6 = 0.285

M7 = 7.0

Step-by-step explanation:

(20,40)-(15,30)=(5,10), m1=5/10=0.5

(18,48)-(12,32)=(6,16), m2=3/8=0.375

(72,32)-(27,12)=(45,20), m3=9/4=2.25

(60,20)-(45,15)=(15,5), m4=3.0

(243,18)-(27,2)=(216,16), m5=27/2=13.5

(24,84)-(18,63)=(6,21), m6=2/7=0.285...

(84,12)-(63,9)=(21,3), m7=7.0

4 0
3 years ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

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What is the constant difference for a hyperbola with foci (-3.5, 0) and (3.5, 0) and a point on the hyperbola (3. 5, 24)?
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