Point slope: y - y1 = m(x - x1), m is the slope

first picture

points (-4,-1) and (3,-3)
the slope between these points is

slope = (-3 - 1)/( 3 - (-4) ) = -2/7

if (x1, y1) = (-4, -1), then the slope-point form is

y + 1 = -2/7(x + 4)

___________

second picture (horizontal line)

from the graph, the slope is 0 because there is no rise for a horizontal line.
if (x1, y1) = (-2, 1), then the point slope form is

y - 1 = 0(x + 2)

_____________

third picture

from the graph, we have points (-2,2) and (2,-2) on the line. the slope is

slope = (-2 - 2)/(2 - (-2) ) = -1

if (x1, y1) = (-2,2), then point slope form is

y - 2 = -1(x + 2)

______________

fourth picture

if points (-2,-1) and (2,1) are on the graph, then slope is

slope = (1 - (-1) ) / (2 - (-2) ) = 1/2

with (x1, y1) = (-2,-1), the point slope form is

y + 1 = 1/2(x + 2)

_______________

fifth picture

we have points (-1,-2) and (1,2). the slope is

slope = (2 - (-2) ) / (1 - (-1) ) = 2

with (x1, y1) = (1,2), the point slope form is

y - 2 = 2(x - 1)

8 0

3 years ago

When the points below are connected, they will form triangle ABC. Show and state whether this triangle has a right angle or not.

cluponka [151]

Answer:

See explanartions below

Step-by-step explanation:

Given the coordinates A(-6,3) B(0,5) C(2,-1)

We first need to get the slope of AB, BC and AC

For AB;

A(-6,3) B(0,5)

Mab = 5-3/0-(-6)

Mab = 2/6

Mab = 1/3

For BC;

B(0,5) C(2,-1)

Mbc = -1-5/2-0

Mbc = -6/2

Mc = -3

For AC:

A(-6,3) C(2,-1)

Mac = -1-3/2-(-6)

MAc = -4/8

Mac = -1/2

Taking the product of Mab and Mbc

Mab * Mbc = 1/3 + -3

Mab * Mbc = -1

<em>Since the product of Mab and Mbc is -1, hence AB abd BC are perpendicular showing that one of the angle of triangle ABC is 90 degrees</em>

8 0

4 years ago