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Brilliant_brown [7]
3 years ago
15

Simplify 25^ - 1/2 Please explain! I know the answer is 1/5 but why?

Mathematics
1 answer:
lisov135 [29]3 years ago
3 0

(25)^{-\frac{1}{2} }

When the exponent is negative, you have to make the number a fraction(1 over the number).

For example:

25^{-2} = \frac{1}{25^{2} }

x^{-1} =\frac{1}{x^{1}  }

This gets rid of the negative, but it leaves the exponent

(25)^{-\frac{1}{2}}  = \frac{1}{25^{1/2}}

When an exponent is a fraction, it is the square root.

For example:

x^{\frac{1}{3}} =  \sqrt[3]{x}

x^{\frac{1}{2}}  =\sqrt{x}

x^{\frac{1}{4}}=\sqrt[4]{x}

So...

\frac{1}{25^{1/2}} = \frac{1}{\sqrt{25}  } = \frac{1}{5}

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3 years ago
a rectangular prism has a length on 20in a width of 2 in and a height of 3 1/4in. the prism is filled with cubes that have an ed
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Determine the probability of randomly selecting two individuals who are issued exactly two credit cards.​ [Hint: Are the events​
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Answer:

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Step By Step Explanation:

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If csc x = −5, find csc(−x) find the period and horizontal shift
ella [17]

Answer:

\csc (-x) = - \csc x = - ( - 5) = 5

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Step-by-step explanation:

We know that \sin (-x) = - \sin x and as \csc x = \frac{1}{\sin x}, so, we can write \csc (-x) = - \csc x

Therefore, the if \csc x = - 5 then \csc (-x) = - \csc x = - ( - 5) = 5 (Answer)

Now, the period of \csc x is 2π, hence the period of \csc (- x) is also 2π.  (Answer)

Again. \csc ( - x) = \csc (-x + 0), hence, the horizontal shift of \csc (- x) is 0. (Answer)

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