All categories

4 years ago

I need helpppppp with this

Mathematics

1 answer:

kotegsom [21]4 years ago

4 0

Answer:

to have or take an inclined or oblique direction or angle considered with reference to a vertical or horizontal plane

Step-by-step explanation:

You might be interested in

Which of the following word problems can be solved using the equation 12 ÷ 4 = a?

Sever21 [200]

Answer:

Step-by-step explanation:

A) 12 is divided by 4 since the twelve cookies are shared equally between four children.

B) 12 is multiplied by 4 since each band uniform has 12 buttons and there are four band uniforms.

C) 12 is substracted by 4 since four boats will not participate in the race out of a total of 12 boats.

D) 4 is added to 12 since there are already 12 monkeys but now 4 more will arrive.

7 0

3 years ago

Read 2 more answers

What is the value of x in the equation 2|3(1|2x+12)=1|2(1|3x+14)-3

lubasha [3.4K]

Answer:

x=-24

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the solution to the equation below? 5 - n/2 = 12

Zarrin [17]

Step-by-step explanation:

5 - n/2 = 12

10/2 - n/2 = 12

n = (12 × (-2)) + 10

n = (-24) + 10

n = -14

Let's prove it :

$5 - ( - \frac{14}{2} ) \\ = \frac{10}{2} + \frac{14}{2} \\ = \frac{24}{2} \\ = 12$

Conclusion :

5 - n/2 = 12

5 - (-14/2) = 12

and

n = -14

8 0

3 years ago

A rectangular box is to have a square base and a volume of 72 ft3. If the material for the base costs $0.62/ft2, the material fo

Igoryamba

Answer:

a. length = 0.7211 ft

b. width = 0.7211 ft

c. height = 140.3846 ft

Step-by-step explanation:

This is an optimiztion with restriction problem.

We have to minimize the cost, with the restriction of the volume being equal to 72 ft3.

As the cost for the sides is constant, we know that length and width are equal.

Then, we can express the volume as:

$V=x\cdot y\cdot z=x^2z=73$

being x: length and z: height

We can express the height in function of the length as:

$x^2z=73\\\\z=73x^{-2}$

Then, the cost of the box can be expressed as:

$C=0.62(x^2)+4*0.15(xz)+0.18(x^2)=(0.62+0.18)x^2+0.60xz\\\\C=0.8x^2+0.60x*x^{-2}=0.8x^2+0.6x^{-1}$

To optimize C, we derive and equal to zero

$\dfrac{dC}{dx}=\dfrac{d}{dx}[0.8x^2+0.6x^{-1}]=1.6x-0.6x^{-2}=0\\\\\\1.6x=0.6x^{-2}\\\\x^{1+2}=0.6/1.6=0.375\\\\x=\sqrt[3]{0.375} =0.7211$

The height z is then

$z=73x^{-2}=\dfrac{73}{0.7211^2}=\dfrac{73}{0.52}=140.3846$

6 0

3 years ago

What is the slope of the line and NO LINKS

Alenkinab [10]

Answer:i would 1*/

Step-by-step explanation: because

3 0

3 years ago