Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
If you mean 3.4444.. then the answer is 3 4/9 as a mixed number and 31/9 as an improper fraction
Answers:
1. a) 4.1x + 29
2. b) 1/5(m – 100)
3. c) nine over five y + 9 (9/5y + 9)
Explanations:
1. The formula for perimeter of a triangle is P = side a + side b + side c, so with these values it is:
2.3x + 14 + 2x – .2x + 15
Combine like terms:
4.1x + 29
2. Test the options to see which ones work out to the answer. You know that 1/5 of 100 = 20, so you need one with a 100 and a 1/5 in it. The only possible answer is:
1/5(m – 100)
3. Distribute the 3/5:
3/5 • 3y + 3/5 • 15 = 9/5y + 45/5 = 9/5y + 15
Answer:
f^-1(x) = (x + 4) / -5
Step-by-step explanation:
f(x) = -5x - 4 Substitute f(x) with y
y = -5x - 4 Switch the x and y variables
x = -5y - 4 Solve it down
x + 4 = -5y
y = (x + 4)/ -5
f^-1(x) = (x + 4) / -5 <----- This is the answer
Answer:
33
Step-by-step explanation:
let Elga age be x
And So Alvin age is x+15
x+x+15=81
2x+15=81
2x=81-15
2x=66
x=66/2
x=33
