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shusha [124]
3 years ago
15

Elimination_4x_2y=14 _10x+7y=_24

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

The answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

Step-by-step explanation:

Given:

-4x-2y=14

-10x+7y=-24

Now, to solve it by elimination:

-4x-2y=14   ......(1)

-10x+7y=-24 ......(2)

So, we multiply the equation (1) by 7 we get:

-28x-14y=98

And, we multiply the equation (2) by 2 we get:

-20x+14y=-48

Now, adding both the new equations:

-28x-14y+(-20x+14y)=98+(-48)

-28x-14y-20x+14y=98-48

-28x-20x-14y+14y=50

-8x=50

<em>Dividing both the sides by -8 we get:</em>

x=-\frac{50}{8}

Now, putting the value of x in equation (1):

-4x-2y=14

-4(-\frac{50}{8})-2y=14

\frac{200}{8} -2y=14

25-2y=14

<em>Subtracting both sides by 25 we get:</em>

-2y=-11

<em>Dividing both sides by -2 we get:</em>

y=\frac{11}{2}

Therefore, the answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

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Mariulka [41]

Answer:

x = 12

Step-by-step explanation:

Remark

These two angles are corresponding angles and as such, they are equal.

Equation

8x+ 36 = 5x + 72

Solution

Subtract 5x from both sides

8x - 5x + 36 = 5x - 5x + 72          Combine like terms.

3x + 36 = 72                                 Subtract 36 from both sides

3x + 36 - 36 = 72 - 36                  Collect like terms

3x = 36                                          Divide by 3

3x/3 = 36/3                                   Divide

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6 0
3 years ago
I need help with multiplying and dividing powers
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You need to know these two formulas:

\huge a^b \times a^c = a^{b+c}\\\\\huge \frac{a^b}{a^c}=a^{b-c}

For example,

5^2 \times 5^3 = 5^{2+3} = 5^5

\frac{2^6}{2^4} = 2^{6-4} = 2^2
6 0
3 years ago
A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
marta [7]

Answer:

(a) The probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b) <em>n</em> = 28.09

Step-by-step explanation:

The random variable <em>Y</em>ₙ is defined as the total numbers of dollars paid in <em>n</em> years.

It is provided that <em>Y</em>ₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of <em>Y</em>ₙ are:

\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}

(a)

For <em>n</em> = 20 the mean and standard deviation of <em>Y</em>₂₀ are:

\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\

Compute the probability that <em>Y</em>₂₀ exceeds 1000 as follows:

P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z>  4.47)\\=1-P(Z

**Use a <em>z </em>table for probability.

Thus, the probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b)

It is provided that P (<em>Y</em>ₙ > 1000) > 0.99.

P(Y_{n}>1000)=0.99\\1-P(Y_{n}

The value of <em>z</em> for which P (Z < z) = 0.01 is 2.33.

Compute the value of <em>n</em> as follows:

z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n}  \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0

The last equation is a quadratic equation.

The roots of a quadratic equation are:

n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of <em>n</em> = 28.09.

8 0
3 years ago
If you take a number, times by 7 then subtract 1. You get the same as if you took the number, times by 5 then subtract 8. What i
valentinak56 [21]

Answer:

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Step-by-step explanation:

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3 years ago
A media company wants to track the results of its new marketing plan, so the video production manager recorded the number of vie
Alisiya [41]

Answer:

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Step-by-step explanation:

As per the given question

As we know that

f(x) and x are related by following equation

f(x)=a( {b})^{x}

where

b is the common ratio

Now first we have to compute the value for b which are as follows

\frac{6400}{5120}= 1.25

\frac{8000}{6400}= 1.25

Like if we take the ratio by this method than it comes 1.25

Therefore the common ratio, b = 1.25

So,

a = 5,120

Hence, the equation which model the relationship between the number of weeks and the number of viewers is

f(x)=5120(1.25)^{x}

8 0
3 years ago
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