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shusha [124]
3 years ago
15

Elimination_4x_2y=14 _10x+7y=_24

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

The answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

Step-by-step explanation:

Given:

-4x-2y=14

-10x+7y=-24

Now, to solve it by elimination:

-4x-2y=14   ......(1)

-10x+7y=-24 ......(2)

So, we multiply the equation (1) by 7 we get:

-28x-14y=98

And, we multiply the equation (2) by 2 we get:

-20x+14y=-48

Now, adding both the new equations:

-28x-14y+(-20x+14y)=98+(-48)

-28x-14y-20x+14y=98-48

-28x-20x-14y+14y=50

-8x=50

<em>Dividing both the sides by -8 we get:</em>

x=-\frac{50}{8}

Now, putting the value of x in equation (1):

-4x-2y=14

-4(-\frac{50}{8})-2y=14

\frac{200}{8} -2y=14

25-2y=14

<em>Subtracting both sides by 25 we get:</em>

-2y=-11

<em>Dividing both sides by -2 we get:</em>

y=\frac{11}{2}

Therefore, the answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

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Answer:

Step-by-step explanation:

This isn't the same thing although you will get some factors that have i in them

(x^4 - 64) factors using the difference of squares.

(x^2 - 8)(x^2 + 8) Both of these factor using the difference of squares.

(x^2 - 8): factors into (x + sqrt(8) )(x - sqrt(8) )

(x^2 - 8):  factors further (x + 2*sqrt2)(x - 2sqrt(2)

(x ^2 + 8) : (x + sqrt(8)i ) (x - sqrt(8)i )

(x^2 + 8) : (x + 2sqrt(2)i) (x - 2sqrt(2)i)

Final answer

(x + 2*sqrt2)(x - 2sqrt(2)(x + 2*sqrt2)(x - 2sqrt(2)

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3 years ago
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2 years ago
Use the parabola tool to graph the quadratic function f(x)=−12x2+7. Graph the parabola by first plotting its vertex and then plo
Fudgin [204]
First we find the vertex of parabola f(x)=-12 x^{2} +7

The vertex of parabola is ( \frac{-b}{2a},f( \frac{-b}{2a}))
Here,
b = coefficient of x term
a = coefficient of x² term

For given parabola, b = 0 , a = -12

So,
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And,

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Thus the vertex of parabola is (0, 7)

To find another point on parabola, substitute x by 1.

f(1)=-12( 1^{2}) +7=-12+7=-5

So the second point on parabola is (1,-5)

The plot of parabola is shown in image below:

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