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notsponge [240]
3 years ago
13

An employee’s total weekly pay equals the hourly wage multiplied by the total number of regular hours plus any overtime pay. Ove

rtime pay equals the total overtime hours multiplied by 1.5 times the hourly wage. Write a program that takes as inputs the hourly wage, total regular hours, and total overtime hours and displays an employee’s total weekly pay.
Computers and Technology
1 answer:
Feliz [49]3 years ago
3 0

Answer:

C++ programming language is used to implement this program using Dev C++. You can use any C++ compiler to run this program. The code and its explanation is given below in explanation section.

Explanation:

#include<iostream>

using namespace std;

int main()

{

int totalWeeklyPay;//total weekly pay  

int hourlyWage;// wages per hours

 

int totalRegularHour;// total regular hours worked

int totalOverTimeHour;// total over time hours worked

 

int weeklyTotalRegularPay;

int weeklyTotalOverTimePay;

 

cout<<"Enter Wage per hour: ";

 cin>>hourlyWage;

 if (hourlyWage<0)//if use enter negative value

  {

   cout<<"Please enter positive number number for wage per hour\n";

   cout<<"Enter Wage per hour: ";

     cin>>hourlyWage;

  }

cout<<"Enter total regular hour: ";

cin>>totalRegularHour;

if (totalRegularHour<0)//if user enter negative value

  {

   cout<<"Please enter positive total number of regular hour\n";

  cout<<"Enter total regular hour: ";

     cin>>totalRegularHour;

  }

cout<<"Enter total over time hour: ";

cin>>totalOverTimeHour;

 

 if(totalOverTimeHour<0)//if user enter negative value

   {

    cout<<"Please enter positive total number of over time hour\n";

  cout<<"Enter total over time hour: ";

  cin>>totalOverTimeHour;

     

     

 }

 

weeklyTotalRegularPay =hourlyWage*totalRegularHour;// total weekly regular hour pay

weeklyTotalOverTimePay=totalOverTimeHour*hourlyWage*1.5;// total weekly overtime pay

totalWeeklyPay=weeklyTotalRegularPay + weeklyTotalOverTimePay;//total weekly regular hour pay + // total weekly overtime pay

cout<<"Total Weekly Pay is: "<<totalWeeklyPay<<"$";//output

 

 

return 0;

 

}

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DochEvi [55]

Answer:

It's content will be replaced with a content from the source cell.

7 0
3 years ago
What layer of the OSI model describes how data between applications is synced and recovered if messages don't arrive intact at t
lina2011 [118]

Answer:

C) Session Layer.

Explanation:

OSI model stands for Open Systems Interconnection. The seven layers of OSI model architecture starts from the Hardware Layers (Layers in Hardware Systems) to Software Layers (Layers in Software Systems) and includes the following;

1. Physical Layer

2. Data link Layer

3. Network Layer

4. Transport Layer

5. Session Layer

6. Presentation Layer

7. Application Layer

Basically, each layer has its unique functionality which is responsible for the proper functioning of the communication services.

Session layer is the layer of an Open Systems Interconnection (OSI) model which describes how data between applications is synced and recovered if messages don't arrive intact at the receiving application.

3 0
2 years ago
Write a program that reads a string of characters, pushing each character onto a stack as it is read and simultaneously adding i
sleet_krkn [62]

Answer:

#include <iostream>

#include <stack>

#include <queue>

#include <string>

int main()

{

   while ( true )

   {

       std::string letters;

       std::cout << "Please enter a word (Enter - exit): ";

       std::getline( std::cin, letters );

       if ( letters.empty() ) break;

       std::stack<char>

           s( std::stack<char>::container_type( letters.begin(), letters.end() ) );

       std::queue<char>

           q( std::queue<char>::container_type( letters.begin(), letters.end() ) );

       while ( !s.empty() && s.top() == q.front() )

       {

           s.pop();

           q.pop();

       }

if ( s.empty() ) std::cout << "The word is a palindrome" << std::endl;

       else std::cout << "The word is not a palindrome" << std::endl;

   }

   return 0;

}

Explanation:

A <em>stack</em> is used to replicate a stack data structure in C++  while <em>Queue </em>container is a replica of the queue data structure in C++, Unlike stack, in the queue container, there are two ends, i.e. front, and back.

In the code above to be able to use used stack and queue, we included the headers #include <stack> and#include <queue>.

4 0
3 years ago
An interrupt priority scheme can be used to ____. allow the most urgent work to be finished first make it possible for high-prio
Nana76 [90]

Answer:

All of the above

Explanation:

An interrupt priority scheme is a system which decides the priority at which various work is done and it perform all of the above mention task so therefore all of the above is the right answer.

5 0
3 years ago
What is output? public class MathRecursive { public static void myMathFunction(int a, int r, int counter) { int val; val = a*r;
ycow [4]

Answer:

The output of the program is:

2 4 8 16 32 64 End

Explanation:

See attachment for proper presentation of the program

The program uses recursion to determine its operations and outputs.

The function is defined as: myMathFunction(int a, int r, int counter)

It initially gets the following as its input from the main method

a= 1; r = 2; counter = 0

Its operation goes thus:

val = a*r; 1 * 2 = 2

Print val; Prints 2

if (counter > 4) { System.out.print("End"); } : Not true

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 2; r = 2; counter = 1

val = a*r; 2 * 2 = 4

Print val; Prints 4

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 4; r = 2; counter = 2

val = a*r; 4 * 2 = 8

Print val; Prints 8

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 8; r = 2; counter = 3

val = a*r; 8 * 2 = 16

Print val; Prints 16

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 16; r = 2; counter = 4

val = a*r; 16 * 2 = 32

Print val; Prints 32

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 32; r = 2; counter = 5

val = a*r; 32 * 2 = 64

Print val; Prints 64

if (counter > 4) { System.out.print("End"); } : True

<em>This prints "End"</em>

So; the output of the program is:

2 4 8 16 32 64 End

3 0
2 years ago
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