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Vadim26 [7]
3 years ago
15

If point b(6,4) undergoes the following translation (x-8,y+2) what are the coordinates of point b’

Mathematics
1 answer:
Leno4ka [110]3 years ago
7 0

Answer:

(-2,6)

Step-by-step explanation:

If b is (6,4) and we have b' is the image that follows from the translation

(x-8,y+2).

Basically the image of (x,y) is (x-8,y+2).

So the image of (6,4) is (6-8,4+2).

Simplify:

(6-8,4+2)

(-2,6).

b' is (-2,6).

You might be interested in
Write the equation of the line that has the indicated slope and contains the indicated point. Express the final equation in stan
OlgaM077 [116]

Answer:

y = 1/2x + 5

Step-by-step explanation:

Given :

Slope, m = 1/2

(x1, y1) = (6, 8)

y - y1 = m(x - x1)

y - 8 = 1/2(x - 6)

y - 8 = 1/2x - 3

y - 8 + 8 = 1/2x - 3 + 8

y = 1/2x + 5

Stamdard form of equation :

y = mx + c

Hence, equation is :

y = 1/2x + 5

7 0
3 years ago
If the angle NME = x+97, the angle EML = x+66, and the angle NML = 141, find the angle EML
defon

Answer:

∠ EML = 94°

Step-by-step explanation:

See the attached diagram.

The three angles ∠ NME, ∠ EML and ∠ NML together make 360°.

Now, ∠ NME = x + 97, ∠ EML = x + 66 and ∠ NML = 141°

Hence, (x + 97) + ( x + 66) + 141 = 360

⇒ 2x + 304 = 360

⇒ 2x = 56

⇒ x = 28

So, ∠ EML = x + 66 = 28 + 66 = 94° (Answer)

6 0
3 years ago
Anybody know the answers?
muminat

Answer:

1 adult = 16 students

a = 16x

Step-by-step explanation:

4 0
3 years ago
Just give me answer
atroni [7]

By applying the equation of dilation, the coordinates of the vertices of the triangle ABC are A'(x, y) = (-12, 0), B'(x, y) = (0, -9) and C'(x, y) = (-12, -9).

<h3>How to find the image of a triangle</h3>

A dilation is a type of <em>rigid</em> transformation. <em>Rigid</em> transformations are transformations applied to <em>geometric</em> loci such that <em>Euclidean</em> distances are conserved.

There is a triangle and its image must be a triangle, the <em>new</em> triangle is found by transforming the three vertices of the prior one following this formula:

A'(x, y) = P(x, y) + k · [A(x, y) - P(x, y)]     (1)

Where:

  • P(x, y) - Center of reflection.
  • A(x, y) - Original vertex
  • A'(x, y) - New vertex
  • k - Dilation factor

If we know that P(x, y) = (0, 0), A(x, y) = (-4, 0), B(x, y) = (0, -3) and C(x, y) = (-4, -3), then the new vertices of the triangle are, respectively:

Point A

A'(x, y) = (0, 0) + 3 · [(-4, 0) - (0, 0)]

A'(x, y) = (-12, 0)

Point B

B'(x, y) = (0, 0) + 3 · [(0, -3) - (0, 0)]

B'(x, y) = (0, -9)

Point C

C'(x, y) = (0, 0) + 3 · [(-4, -3) - (0, 0)]

C'(x, y) = (-12, -9)

Lastly, we draw the two triangles, which are presented in the image attached below.

To learn more on dilations: brainly.com/question/13176891

#SPJ1

6 0
2 years ago
Read 2 more answers
Please help with this khan academy question
Ksenya-84 [330]

Answer:

<A = 30°

Step-by-step explanation:

5x - 18 = 3x + 42

2x = 60

60/2 = 30

<A = 30°

hope this helps :)

4 0
3 years ago
Read 2 more answers
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