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Mathematics

1 answer:

Karolina [17]2 years ago

8 0

Answer:

Step-by-step explanation:

Don't worry about the volume to start with. Just look at the area of the top or bottom.

The hole has a 4 inch diameter

d = 4

r = d/2

r = 2

Area = pi r^2

Area = pi * 2^2

Area = 4 pi

Now find the area of the top (or bottom) if the circle was not there.

L = 8

W = 6

Area = L * W

Area = 8 * 6

Area = 48

Now take away the area of the circle.

Area Top = 48 - 4 * pi

Area Top = 48 - 12.56

Area Top = 35.44

Finally, Find the volume

Volume = area of the top * height

Volume = 35.44 * 15

Volume = 531.6

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A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$