Answer:
CREATE VIEW [product_summary] AS
SELECT product_id , order_count , order_total FROM Product;
SELECT * FROM [product_summary] ;
Explanation:
- First of all, use the CREATE VIEW syntax to create a view named product_summary that includes the product_id, order_count, order_total columns and returns the summary information about each product.
- Use SELECT statement to return all the columns from the product_summary view.
Answer:
Following are the answer to this question:
Explanation:
In option 1:
The value of n is= 7, which is (base case)
when n=k for the true condition:
when n=k+1 it tests the value:
since k>6 hence the value is KH>3 hence proved.
In option 2:
when:
for n=1:(base case)
0<=0 \\ condition is true
when the above statement holds value n=1
when n=k
when n=k+1
![[\therefore KH>K \Rightarrow \log(KH>\loK)]](https://tex.z-dn.net/?f=%5B%5Ctherefore%20KH%3EK%20%5CRightarrow%20%20%5Clog%28KH%3E%5CloK%29%5D)
In option 3:
when n=1:
when n=k
![\to (A_1\cap A_2 \cap.....A_k) \cup B\\=(A_1\cup B) \cap(A_2\cup B_2)....(A_k \capB).....(a)\\\to n= k+1\\ \to (A_1\cap A_2 \cap.....A_{kH}) \cup B= (A_1\cup B)\\\\\to [(A_1\cap A_2 \cap.....A_{k}) \cup B]\cap (A_{KH}\cup B)\\\\\to [(A_1\cup B) \cap (A_2 \cup B) \cap (A_3\cup B).....(A_k\cup B)\cap (A_{k+1} \cup B)\\\\ \ \ \ \ \ \ substituting \ equation \ a \\\\](https://tex.z-dn.net/?f=%5Cto%20%28A_1%5Ccap%20A_2%20%5Ccap.....A_k%29%20%5Ccup%20B%5C%5C%3D%28A_1%5Ccup%20B%29%20%5Ccap%28A_2%5Ccup%20B_2%29....%28A_k%20%5CcapB%29.....%28a%29%5C%5C%5Cto%20n%3D%20k%2B1%5C%5C%20%5Cto%20%28A_1%5Ccap%20A_2%20%5Ccap.....A_%7BkH%7D%29%20%5Ccup%20B%3D%20%28A_1%5Ccup%20B%29%5C%5C%5C%5C%5Cto%20%20%5B%28A_1%5Ccap%20A_2%20%5Ccap.....A_%7Bk%7D%29%20%5Ccup%20B%5D%5Ccap%20%28A_%7BKH%7D%5Ccup%20B%29%5C%5C%5C%5C%5Cto%20%20%5B%28A_1%5Ccup%20B%29%20%5Ccap%20%28A_2%20%5Ccup%20B%29%20%5Ccap%20%28A_3%5Ccup%20B%29.....%28A_k%5Ccup%20B%29%5Ccap%20%28A_%7Bk%2B1%7D%20%5Ccup%20B%29%5C%5C%5C%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20substituting%20%5C%20equation%20%5C%20a%20%5C%5C%5C%5C)
hence n=k+1 is true.
D will be the answer a program that allows you to take a tutorial on html terminology
Answer:
#include <bits/stdc++.h>
using namespace std;
int main() {
string email,username,host;//strings to store email,username,hostname..
cout<<"Enter the email address "<<endl;
cin>>email;//taking input of email address..
bool flag=1;
for(int i=0;i<email.length();i++)//iterating over the string email..
{
if(email[i]=='@')//if @ symbol is encountered make flag 0 skip this iteration.
{
flag=0;
continue;
}
if(flag==1)//add to username if flag is 1.
{
username+=email[i];
}
else//add tom host..
host+=email[i];
}
cout<<"The username is "<<username<<endl<<"The host name is "<<host;//printing the username and hostname..
return 0;
}
Explanation:
I have taken three strings to store the email address entered by user ,username and host to store username and host name respectively.Then I am iterating over the string email if @ is encountered then skip that iteration before that keep adding characters to username string and after that keep adding characters to host.
The answer is Tablets. It is a portable personal computer, generally with a mobile operating system and LCD touchscreen display processing circuitry, and a rechargeable battery in a single thin, flat package. It is bigger than smartphones.
