Answer:
- vertex: (-5/8, 7/16)
- axis of symmetry: x = -5/8
Step-by-step explanation:
For quadratic ax²+bx+c, the axis of symmetry is located at x=-b/(2a).
Here, we have a=4, b=5, so the axis of symmetry is ...
... x = -5/(2·4) = -5/8
_____
The vertex y-value will be f(-5/8).
... f(-5/8) = (4·(-5/8) +5)·(-5/8) +2 = (5/2)·(-5/8) +2 = -25/16 +32/16
... f(-5/8) = 7/16
_____
The axis of symmetry is x = -5/8; the vertex is (-5/8, 7/16).
Answer:
<u>Given:</u>
- DC ║ AB
- CM = MB as M is midpoint of BC
i) <u>Since DN and BC are transversals, we have:</u>
- ∠DCM ≅ ∠NBM and
- ∠CDM ≅ ∠BNM as alternate interior angles
<u>As two angles and one side is congruent, the triangles are also congruent:</u>
- ΔDCM ≅ ΔNBM (according to AAC postulate)
So their areas are same.
ii)
<u>The quadrilateral has area of:</u>
- A(ADCB) = A(ADMB) + A(DCM)
<u>And the triangle has area of:</u>
- A(ADN) = A(ADMB) + A(NBM)
Since the areas of triangles DCM and NBM are same, the quadrilateral ADCB has same area as triangle ADN.
Answer:
maybe rotation.........i think....
Well, since point A represents the center, and B represents a point on the outer line of the circle, segment AB would represent the radius, since the radius represents the length from the center to the outside of a circle
Hope this helps
D = 11
Hope That Helped =D <span />
