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LekaFEV [45]
3 years ago
13

How to solve quadratic equations

Mathematics
1 answer:
eduard3 years ago
8 0
If we have two numbers A&B and we know that A times B=0  then it must follow that either A=0, or B=0 (or both) 
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Mouza, Alreem, Latifa, Zayed and Mohammed are
julia-pushkina [17]

Answer:

900m

Step-by-step explanation: if one is 300m then do 300m x 3 =900m.

Hoped this help

7 0
3 years ago
Multiply the binomials (x + 1)(-5x + 10) *
Leona [35]
So i think here you would FOIL. so -5x^2+10x-5x+10 and then combine like terms :)
7 0
4 years ago
Read 2 more answers
Perimeter/area (triangles) ! PLZ HELP
BartSMP [9]

Answer:

50ft^2

Step-by-step explanation:

area of triangle ABC=25ft^2

both triangle have equal area and all together it makes a rectangle ABCD so ,

rect. ABCD=25+25=50FT^2

3 0
3 years ago
Read 2 more answers
BRAINLIEST
Cloud [144]

10 ways I think if its wrong I'm sorry

3 0
3 years ago
Jo jo has a total amount of $12.45 in quarters and dimes in his pocket. he has a total of 60 coins. how many quarters and dimes
baherus [9]

Given:

Total number of coins (Quarters and dimes) = 60

Total amount = $12.45

To find:

The number of quarters and dimes.

Solution:

Let x be the number of quarters and y be the number of dimes.

We know that,

1 quarter = 0.25 dollar

1 dime = 0.10 dollar

Total coins: x+y=60               ...(i)

Total amount: 0.25x+0.10y=12.45             ...(ii)

From (i), we get

y=60-x          ...(iii)

Putting this value in (ii), we get

0.25x+0.10(60-x)=12.45

0.25x+6-0.10x=12.45

0.25x-0.10x=12.45-6

0.15x=6.45

Divide both sides by 0.15.

x=\dfrac{6.45}{0.15}

x=43

Putting x=43 in (iii), we get

y=60-43

y=17

So, the number of quarters is 43 and the number of dimes is 17.

Therefore, the correct option is b.

8 0
3 years ago
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