The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.
<h3>What is the solution of the equation?</h3>
The solution of the equation means the value of the unknown or variable.
The equation is given below.
x – 2 = √(2x – 1)
Square on both side, then we have
(x – 2)² = 2x – 1
x² – 4x + 4 = 2x – 1
x² – 6x + 5 = 0
x² – 5x – x + 5 = 0
x(x – 5) – 1(x – 5) = 0
(x – 5)(x – 1) = 0
x = 1, 5
The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.
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Answer:..................................................................
The value of a can be obtained by substituting 1 to the
equation and equating p(1) = 0.
<span> p(x) = x2a - 3xa + 3x2 -1 </span>
<span>p(1) = a - 3a +3 -1 = 0</span>
<span>therefore a =1</span>
the equation now becomes p(x) = x2 - 3x + 3x2 -1
To solve this we need to form 2 equations with only 2 variables.
x+4y-5z=-7
2x+y+5z=8
3x+5y=1
15x+10y+15z=35
6x+3y+15z=24
9x+7y=11
Now we need to use these to find x and y
9x+15y=3
9x+7y=11
8y=-8
y=-1
Therefore:
x=2
From this we can find that:
2(2)-1+5z=8
Therefore z=1
The answer is x=2, y=-1, z=1