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Irina-Kira [14]
3 years ago
9

PLEEASEEEEE HEEELP 40 POINTS

Mathematics
2 answers:
cestrela7 [59]3 years ago
4 0

The leading term is , so the graph should resemble a stretched cubic curve reflected across the x axis.

Anna71 [15]3 years ago
3 0

<em>f</em> • <em>g</em> denotes the product of <em>f</em> and <em>g</em>, so that

(f\cdot g)(x)=f(x)\cdot g(x)=(3x-8)(-2x+5)

Without computing the whole product, just look at the first terms, -6x^2. This tells you that <em>f </em>• <em>g</em> is quadratic, and its graph is a stretched parabola that opens downward.

You can treat the product <em>g</em> • <em>s</em> similarly:

(g\cdot s)(x)=(-2x+5)(4x^2-9x+2)

The leading term is -8x^3, so the graph should resemble a stretched cubic curve reflected across the <em>x</em> axis.

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x^2-8x+7=0\\\\a=1;\ b=-8;\ c=7\\\\\Delta=b^2-4ac;\ x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\Delta=(-8)^2-4\cdot1\cdot7=64-28=36;\ \sqrt\Delta=\sqrt{36}=6\\\\x_1=\frac{8-6}{2\cdot1}=\frac{2}{2}=1;\ x_2=\frac{8+6}{2\cdot1}=\frac{14}{2}=7\\\\\\\\Answer:x=0\ or\ x=1\ or\ x=7.
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