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3 years ago

I don’t know where to start on this problem

Mathematics

1 answer:

11111nata11111 [884]3 years ago

6 0

Okay so first of all you are going to cross multiply, which is simply multiplying diagonally across so (6x×5 and 25×3) then you just answer each part and set them equal to each other so (30x=75). Then you just divide 30 on each side which ends up being (x=2.5)

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Kera earns $12 per hour at her job. Every day she also earns $15 for walking her neighbor’s dog. She has decided to save all of

worty [1.4K]

Answer:

nah

Step-by-step explanation:

4 0

3 years ago

Find the total surface area of this triangular prism. 10 cm 6 cm 4 cm 8 cm

timama [110]

Answer:

144

Step-by-step explanation

8x6=48

48 divided by 2=24

24x2=48

4x10=40

8x4=32

4x6=24

add them all together so 48+40+32+24=144

7 0

2 years ago

Option 1: Find x. Show all work.

Ronch [10]

Using law of cosines:

Cos(angle) = adjacent/ hypotenuse

Cos(22) = 12/x

Rewrite to get:

X = 12/cos(22)

Simplify:

X = 12.9424

Round the answer as needed.

5 0

2 years ago

Read 2 more answers

Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i

vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable X be defined as the number of students at a particular college who are smokers

The random variable X follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

$np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10$

Thus, a Normal approximation to binomial can be applied.

So,

$X\sim N(\mu=600, \sigma=\sqrt{120})$

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

= P (X > 280.50)

$=P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z$

*Use a z-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0

3 years ago

Factorise fully 9x squared - 6xy

prisoha [69]

3x(3x-2y)

you have to find a common factor between the two numbers. in this case it's three, so you just divide each number by three.

4 0

3 years ago