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dusya [7]
3 years ago
15

A manufacturer of cheese filled ravioli supplies a pizza restaurant chain. Based on data collected from its automatic filling pr

ocess, the amount of cheese inserted into the ravioli is normally distributed. To make sure that the automatic filling process is on target, quality control inspectors take a sample of 25 ravioli. The correct value of t* to construct a 98% confidence interval for the true mean amount of cheese filling is ________. Group of answer choices 2.797 2.492 2.064 3.467 3.745
Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

The correct value is t* = 2.492.

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.492, which is the answer to this question.

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Bezzdna [24]

Answer:

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3 years ago
the problem is kamala had 5,026 grams  flour in a canister.she brought a 4,158 gram bag of flour.she poured some flour from the
andrey2020 [161]
Hello, 

x= amount of flour that she poured in the canister

there was 5,026 grams of flour, and now: 5,026+x

In the bag there was 4,158, now: 4,158

I says that as a result the mass of the flour in the canister is twice the mass of the flour left in the bag, so:

5,026+x=2*(4,158-x) \\ 5,026+x=8,316-2x \\ 3x=8,316-5,026 \\ 3x=3,290 \\ x=1,096.67

So, she poured 1,096.67 grams, we subtract this from the initial amount in the bag and we have the answer:

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Answer: there is 3,061.33 grams of flour in the bag
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