Answer:
Terms are 2 , 3 , 7 , 31
Step-by-step explanation:
1) given a1 = 2
an+2 = 2(an) -1
put n = 1
a1 + 2 = 2a1 -1
put value of a1 in above
you'll get a3 = 2² -1
a3 = 4-1
a3 = 3
put n = 3
a3 + 2 = 2a3 -1
a5 = 2³-1
a5 = 8-1
a5 = 7
put n = 5
a5 + 2 = 2a5 -1
a7 = 2⁵ -1
a7 = 32 -1
a7 = 31
Hope you got it.
Similarly you can find 2nd one's term t23
tn = 5*n -4
here n = 23
t23 = 5 * 23 - 4
t23 = 115 -4
t23 = 111
Hope this helps you.
What do you mean by that question?
Step-by-step explanation:
10=4+2s
2s=10-4
2s=6
s=6/2
s=3
The value of the discriminant is the value of

located inside the square root of the quadratic formula. To find this, we simply look at the quadratic equation in standard form:

and plug in the existing values into the quadratic formula (

. Plug in the values of a b and c (2, 7, and -4, respectively) and get

.
Simplifying this, we get

which equal 1/2 and -4, respectively.
A )The value of the discriminant is 81 (see work above)
B ) 2 solutions, discriminant is positive, and not equal to zero. They are both rational since sqrt 81 is a rational number
C ) 1/2 and -4 (see work above)
It’s D
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