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2 years ago

8

Teachers receive 30% educators discount at a museum. An adult ticket costs $24. How much would a teacher pay for admission into

the museum?

1 answer:

viktelen [127]2 years ago

5 0

Answer:

$16.80

Step-by-step explanation:

0.30 × 24 = 7.20

24 - 7.20 = $16.80

Hope that helps.

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25 points!! Which table shows 4 points on the line that passes through the point (–1,5) and has the same slope as the line 2x+3y

mylen [45]

It is the third one hope this helped

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2 years ago

In a calculus class, Jack Hartig scored 4 on a quiz for which the class mean and standard deviation were 2.9 and 2.1, respecti

nataly862011 [7]

Answer: Norm Alpina did better with z-score 0.79

Step-by-step explanation:

Z score formula = (raw score - mean) / standard deviation

For Jack Hartig,

score = 4; mean = 2.9; standard deviation = 2.1

Hence, Z score = (4 - 2.9) /2.1

= 1.1/2.1

= 0.52

For Norm Alpina,

score = 8; mean = 6.5; standard deviation = 1.9

Hence, Z score = (8 - 6.5) /1.9

= 1.5/1.9

= 0.79

Relatively, Norm Alpina did better for having Z score 0.79

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2 years ago

What is the coefficient of x2 in this trinomial?

Scorpion4ik [409]

Answer:1

Step-by-step explanation:

(x+2)(x+3)

x^2+3x+2x+6

x^2+5x+6

Therefore the coefficient of x^2 is 1

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2 years ago

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The function s(V) = Negative RootIndex 3 StartRoot uppercase V EndRoot describes the side length, in units, of a cube with a vol

aliya0001 [1]

Answer:

The Answer is B) s > 4

Step-by-step explanation:

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2 years ago

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A market research team thinks that their new ad campaign is better than their old one. They used to be able to sell to 50% of th

andreev551 [17]

Answer:

a. The test statistic is 2 and we conclude that the new ad campaign is not signficantly better.

Step-by-step explanation:

They used to be able to sell to 50% of those who saw their ads. Test if the new campaign is better.

At the null hypothesis, we test is it is the same, that is, the proportion is the same.

$H_0: p = 0.5$

At the alternate hypothesis, we test if it is significantly better, that is, the proportion is above 50%.

$H_1: p > 0.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that $\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5$

They take a random sample of 100 potential buyers and find that they convinced 60 of these people to buy their product.

This means that $n = 100, X = \frac{60}{100} = 0.6$

Test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.6 - 0.5}{\frac{0.5}{\sqrt{100}}}$

$z = 2$

The test statistic is 2.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.6, which is 1 subtracted the by p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

The p-value of the test is 0.0228 > 0.01, which means that we cannot conclude that the new ad campaign is signficantly better, so the correct answer is given by option A.

5 0

2 years ago