Assume that XY=MN . Which of the following statements are true? (Assume that X, Y, M, N, and F are nonzero real numbers, and ass
ume that all expressions have nonzero denominators.) Create an answer using the numbers associated with the true statements. For example, if only 1, 2, and 5 are true, then the answer is 125; if only 3 and 5 are true, then the answer is 35, etc.
1 answer:
Answer:
123
Step-by-step explanation:
The complete question is Assume that X/Y=M/N . Which of the following statements are true? (Assume that X, Y, M, N, and F are nonzero real numbers, and assume that all expressions have nonzero denominators.) Create an answer using the numbers associated with the true statements. For example, if only 1, 2, and 5 are true, then the answer is 125; if only 3 and 5 are true, then the answer is 35, etc
The statements are given in 1st attachment and answer choices are given in 2nd attachment
Let's start by verifying statements 3 and 4 as these are easy to verify
To verify statement 3,
(X+Y)/Y= (M+N)/N
X/Y + 1= M/N + 1
since X/Y=M/N
X/Y + 1= X/Y +1
So statement 3 is true
To verify statement 4,
(X+F)/Y= (M+F)/N
X/Y + F/Y = M/N + F/N
Statement 4 is false
Look at the answer choices, statement 3 is mentioned in option c,d and e. Statement 4 is mentioned in c and d. Since statement 4 is incorrect our answer is option e
You might be interested in
Answer:
The median value will be 8.
Step-by-step explanation:
The simplest way to think of a median is as a sort of "middle" value. We want to arrange our numbers from lowest to highest, then select the one in the middle. Here is another example:
3, 5, 2, 7, 3, 9, 1, 4, 7
The first step is to order these numbers from lowest to highest, like so:
1, 2, 3, 3, 4, 5, 7, 7, 9
The number in the middle of this set is 4.
The problem you have presented, as well as the above example, both deal with an odd amount of numbers. Your problem has seven numbers, and the example I gave has nine. For any odd amount of numbers, the median is the value in the middle. But what about an even amount of numbers?
Consider:
9, 4, 3, 7
Let's rearrange this:
3, 4, 7, 9
Now, there will be two "middle" values: 4 and 7. The median value will be the average of these two values:
I hope that helps!