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Shkiper50 [21]
3 years ago
13

Write an inequality for the situaions below and solve:

Mathematics
1 answer:
musickatia [10]3 years ago
5 0

Answer

Find out the how many boxes of paper can the forklift move at one time .

To proof

Let us assume that the number of boxes be x.

As given

A forklift can carry up to 2500 pounds.

You want to move boxes of paper which each weigh 140 pounds.

The paper boxes are supported on one pallet which weighs 50 pounds.

Than the equation is become in the form

140x +50  ≥ 2500

140x ≥ 2500 - 50

140x ≥ 2450

x \geq \frac{2450}{140}

x ≥ 17.5

Therefore the 18 boxes of paper can the forklift move at one time .

Hence proved

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Step-by-step explanation:

-5x = 10 + 10

-5x = 20

X = 20/-5

X = -4

check :

-5 x -4 =20

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Answer:

The percent change in runs batted in from 2001 to 2008 is 26.47%

Step-by-step explanation:

The number of runs chipper batted in the year 2001  = 102 runs

The number of runs chipper batted in the year 2008  = 75 runs

Here, so the Change in the runs batted

= Runs Batted in year 2001 - Runs batted in the year 2008

= 102 runs - 75 runs  =  27 runs

Now, The percentage change in the run = = \frac{\textrm{Change in the batted run from 2001 to 2008}}{\textrm{Total number of batted runs in 2001}}  \times 100

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3 years ago
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Answer:

Predicted population of Mexico City in year 2010 = 38386000

Step-by-step explanation:

Formula to be used for the population of Mexico,

P = 20.899e^{0.032t}

Where t = Duration after year 1991

P = Final population

Number of years between 2010 and 1991 = 19 years

Predicted population of Mexico city after 2010 = 20.899e^{0.032\times 19}

                                                                              = 20.899 × (1.8368)

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Therefore, predicted population of Mexico City in year 2010 = 38386000

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Write a two-column proof on a space provided
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Answer:

Step-by-step explanation:

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