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Nataly_w [17]
3 years ago
5

If 1+4=5, 2+5=12, 3+6=21 then 8+11=?

Mathematics
1 answer:
Rashid [163]3 years ago
7 0
In this pattern, 8+11= 8+11 + 77 (the previous answer) = 96
As you go to the next step in the pattern, you add the previous answer as well, so:
1+4=5
2+5= 2+5+5= 12
3+6= 3+6+12 = 21
4+7= 4+7+21 = 32
5+8= 5+8+32 = 45
6+9= 6+9+45 = 60
7+10= 7+10+60 = 77
So 8+11= 8+11+77 +96

I'm not sure how to write this mathematically as such, only in a logical way, but I hope it helps!
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The first term of a geometric series is -3, the common ratio is 6, and the sum of the series is -4,665. Using a table of values,
tamaranim1 [39]

Answer:

Option A. 5

Step-by-step explanation:

From the question given above, the following data were obtained:

First term (a) = –3

Common ratio (r) = 6

Sum of series (Sₙ) = –4665

Number of term (n) =?

The number of terms in the series can be obtained as follow:

Sₙ = a[rⁿ – 1] / r – 1

–4665 = –3[6ⁿ – 1] / 6 – 1

–4665 = –3[6ⁿ – 1] / 5

Cross multiply

–4665 × 5 = –3[6ⁿ – 1]

–23325 = –3[6ⁿ – 1]

Divide both side by –3

–23325 / –3 = 6ⁿ – 1

7775 = 6ⁿ – 1

Collect like terms

7775 + 1 = 6ⁿ

7776 = 6ⁿ

Express 7776 in index form with 6 as the base

6⁵ = 6ⁿ

n = 5

Thus, the number of terms in the geometric series is 5.

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2 years ago
There are 30 students in a class and 18 of them own at least one pet.
katrin2010 [14]

Answer:

18/30=3/5

Step-by-step explanation:

8 0
2 years ago
Superman needs to save Lois. After flying for 10 seconds he is 1520 meters from her then at 15 seconds he is 1230 meters from he
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Average speed is 58 meters per second
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What is the slope of y=-x perpendicular to the equation
tensa zangetsu [6.8K]

\frac{1}{2} x

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2. A square-based tent has the cross-sectional
ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

                                  = 2.732 m

(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

8 0
3 years ago
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