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marshall27 [118]
3 years ago
10

Consider the functions.

Mathematics
2 answers:
ss7ja [257]3 years ago
7 0

Answer:

its c edg 2020

Step-by-step explanation:

katovenus [111]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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Sandy has 18 roses, 9 daisies, and 45 tulips. She wants to arrange all the followers in bouquets. Each bouquet has the same numb
uranmaximum [27]

Answer:

Greatest number of flowers in a bouquet = 9 flowers

Step-by-step explanation:

Total no. of roses = 18

Total no. of daisies = 9

Total no. of tulips = 45

To find the greatest no. of flowers that can be arranged in the bouquet such that there are same number of flowers and same type of flowers in the bouquet, we will take the H.CF (highest common factor) of 18,9,45

H.C.F of 18,9,45 = 9

Hence, the greatest number no. of flowers that can be arranged in the bouquet = 9 flowers.

8 0
3 years ago
Math help only 1 plz help
makvit [3.9K]

Answer:

b=24

Step-by-step explanation:

you use a^2+b^2=c^2

so 10^2+b^2=26^2

100+b^2=676

subtract 100 from both sides

b^2=576

then sq rt the 576 to get 24

7 0
3 years ago
5√48-4√27-2√108+√147
irakobra [83]

Answer:

3\sqrt{3}

Step-by-step explanation:

8 0
3 years ago
True or False Plane KLM and Plane NQR are parallel planes
Nana76 [90]

Answer:

i saed to answer it and it didnt show me the image so im conf

Step-by-step explanation:

so probably they are, unlees one is acxute and the other is obtuse then.... ur on ur own buddy,

3 0
3 years ago
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
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