2 years ago

3^x-3^(x-2)=A*3^x solve for A

Mathematics

1 answer:

ale4655 [162]2 years ago

3 0

Answer:

$a=\frac{8}{9}$

Step-by-step explanation:

$3^x-3x^{x-2} =a3^x$

Divide both sides by $3^x$ :

$3^{x-x}-3^{x-x-2}=a$

Simplify:

$3^0-3^{-2}=a\\a=1-\frac{1}{9} \\a=\frac{8}{9}$

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