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Answer:
a. 5,040 ways
b. 210 ways
Step-by-step explanation:
a) We want to pick 4 numbers out of 10 given that orders matter
If orders do matter, it will be a permutation problem
Mathematically;
n P r = n!/(n-r)!
In this case, n is 10 and r is 4
Thus, we have it that;
10 P 4 = 10!/(10-4)! = 5,040
b) if orders do not matter
It will be a combination problem
n C r = n!/(n-r)!r!
n = 10 and r = 4
10 C 4 = 10! /(10-4)!4!
= 210
Answer:
False
Step-by-step explanation:
Here is a counter example:
● f(x) = x^2
● g(x) = 3x
● (f○g)(x) = (3x)^2 = 9x^2 (1)
● (g○f)(x) = 3(x^2) = 3x^2 (2)
We can see that (1) and (2) aren't equal to each others.
