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3 years ago

Can someone plz help!??ILL GIVE BRAINLIEST TO BEST ANSWER

Mathematics

2 answers:

svetoff [14.1K]3 years ago

6 0

Which question do you want help on?

marishachu [46]3 years ago

6 0

A. Not really. The sample excludes people leaving the school at other times, like those involved in extracurricular activities.
b. The question is biased. The use of the word "lengthy" implies that the day is too long and should be shortened, potentially affecting the students' answers.
c. Roughly 5.6% (rounded to the tenths place)

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Estimate 86 x 904 plz answerrr fastt

malfutka [58]

Answer:

81, 000

Step-by-step explanation:

86 = 90

904 = 900

90 x 900 = 81, 000

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3 years ago

Read 2 more answers

What is 20 divided by 10?

Triss [41]

Answer: 2

Step-by-step explanation: What is 20 divided by 10? 2

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4 years ago

1OO POINTS PLEASE HELP

kondor19780726 [428]

2) Period = 3π,

2π/b = 3π, b = 2π/3π = 2/3

Amplitude = 2

Midline = 1

Equation: f(x) = 3sin(2/3(x)) + 1 (no vertical shift)

See attachment for graph.

3) f(x) = -23sin(4x) + 14,

a) amplitude = 23

b) midline = 14

c) Maximum = 37

d) Minimum = -9

4 0

3 years ago

Harold uses the binomial theorem to expand the binomial (3x^5 - 1/9y^3)^4

riadik2000 [5.3K]

<h3>The complete question:</h3>

Harold uses the binomial theorem to expand the binomial $(3x^5 -\dfrac{1}{9}y^3)^4$

(a) What is the sum in summation notation that he uses to express the expansion?

(b) Write the simplified terms of the expansion.

Answer:

(a). $(3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n} \binom{4}{k}(3x^5)^{4-k}( -\dfrac{1}{9}y^3)^k $$$

(b). $(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561}$

Step-by-step explanation:

(a).

The binomial theorem says

$(x+y)^n=$$\sum_{k=0}^{n} \binom{n}{k}x^{n-k}y^k $$$

For our binomial this gives

$\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n} \binom{4}{k}x^{4-k}y^k $$}$

(b).

We simplify the terms of the expansion and get:

$$$\sum_{k=0}^{n} \binom{4}{k}(3x^5)^{4-k}y^k $$= \binom{4}{0}(3x^5)^{4-0}(-\dfrac{1}{9}y^3 )^0+\binom{4}{1}(3x^5)^{4-1}(-\dfrac{1}{9}y^3 )^1+\\\\\binom{4}{2}(3x^5)^{4-2}(-\dfrac{1}{9}y^3 )^2+\binom{4}{3}(3x^5)^{4-3}(-\dfrac{1}{9}y^3 )^3+\binom{4}{4}(3x^5)^{4-4}(-\dfrac{1}{9}y^3 )^4$

$$$\sum_{k=0}^{n} \binom{4}{k}(3x^5)^{4-k}(-\frac{1}{9}y^3 )^k $$= (3x^5)^{4}+4(3x^5)^{3}(-\frac{1}{9}y^3 )+6(3x^5)^{2}(-\frac{1}{9}y^3 )^2+\\\\4(3x^5)(-\frac{1}{9}y^3 )^3+(-\frac{1}{9}y^3 )^4$

$\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561} }$

3 0

3 years ago

Last year 40 people adopted a manatee through Fia's Foundation.This year 30% more people adopted a manatee. How many more people

Nana76 [90]

Convert 30% into a decimal. Divide the percentage by 100:

$30 / 100 = 0.3$

The problem can be solved with the following equation:

$0.3(40) = difference$

Multiply 0.3 by 40.

$0.3 * 40 = 12$

12 more people adopted a manatee this year.

7 0

3 years ago