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Vikentia [17]
4 years ago
5

Jamal is 167 cm tall which expression expression finds jamals height in dekametres

Mathematics
1 answer:
tensa zangetsu [6.8K]4 years ago
4 0
D

167 cm = 1.67m
1.67m = 0.167dm

D. 167/1000 = 0.167

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How do you use area on funny looking shape
Pepsi [2]

Divide the funny looking shape into many simple common figures and find the area of the common figures. Then add the areas of the figures to find the total area of the funny looking shape.
5 0
3 years ago
Find a whole number between 9 4/9 and the square root of 144
postnew [5]
First, we'll want to write out the equation
9 \frac{4}{9} < n < \sqrt{144}

then reduce what we can
9 \frac{4}{9} < n < 12

so this means n can equal any whole number between 9 4/9 & 12, which gives us the options of {10,11}

n = 10 \: or \: 11
7 0
3 years ago
Solve for x:a(a²+b²)x²+b²x-a​
m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a  

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b²  = (b² + 2a²)²

2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

5 0
3 years ago
50 Points!!
____ [38]

Answer:

a) g(x) = f(x) + 3

So g(x) is a vertical translation of f(x), 3 units upwards

b) g(x) = 3x² - 1 + 3

g(x) = 3x² + 2

The graph has shifted 3 units upwards, so has the vertex.

The vertex of f is (0,-1)

Whereas the vertex of g is (0,2)

-1 + 3 = 2

8 0
3 years ago
Find an equation of variation in which y varies jointly as x and z and inversely as the product of w and​ p, where yequalsstartf
leva [86]

To solve this problem you must apply the proccedure shown below:

1. You have that y varies jointly as x and z and inversely as the product of w and​ p. Therefore, you can write the following equation, where k is the constant of proportionality:

y=k(\frac{xz}{wp} )

2. Now, you must solve for the constant of proportionality, as following:

k=\frac{ywp}{xz}

3. Susbtiute values:

y=\frac{7}{28} \\ x=7\\ z=4\\ w=7\\ p=8

k=\frac{(\frac{7}{28})(7)(8))}{(7)(4)}  =0.5

4. Substitute the value of the constant of proportionality into the equation:

y=0.5(\frac{xz}{wp})

The answer is: y=0.5(\frac{xz}{wp})

7 0
3 years ago
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