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aliina [53]
3 years ago
5

Solve for x:a(a²+b²)x²+b²x-a​

Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

x = a/(a² + b²) or x = -1/a  

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b²  = (b² + 2a²)²

2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

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Lady bird [3.3K]
Ok...we got 250 people
30% are French, 35% are Americans, 20% are Germans....thats 85%.
This means 15% are from other countries

3 not from other countries...
0.85 * 0.85 * 0.85 = 0.6

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5 0
3 years ago
The sum of x and it’s opposite is always zero?
jeka94

Answer:

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

a-a =0

Or in the other case:

-a -(-a) =-a +a=0

So then we can conclude that the expression is a general rule and is true

Step-by-step explanation:

For this case we can verify if the following expression is true or false:

The sum of x and it’s opposite is always zero?

If we want to proof this we need to show that for any number is true.

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

a-a =0

Or in the other case:

-a -(-a) =-a +a=0

So then we can conclude that the expression is a general rule and is true

5 0
3 years ago
Given the following linear function sketch the graph of the function and find the domain and range. f( x ) = 2/7 x− 2
Savatey [412]

Answer:

Domain: All Real Numbers Range: All Real Numbers

Step-by-step explanation:

The domain and range is going to be infinite. The linear function will be using the x and y- axis in order to continue being a function. The y-intercept will be -2 on the y-axis. I recommend using the rise-over-run method for your slope value. from the point (0, -2) on the y-axis. Go up two on the y-axis, and right 7 on the x-axis.

Sorry, it may be difficult to explain through words.

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2 years ago
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BARSIC [14]

Answer:

B

Step-by-step explanation:

Parallel lines have the same slope. The slope of the given line is 3/4. Line B has the same slope.

7 0
3 years ago
Read 2 more answers
Help plssss no links or files or i will report
ra1l [238]

Answer: 350/12

I think 29 2/12 can be also true because they didn't simplify the 2/12 to 1/6.

Step-by-step explanation:

You'll have to use the basic formula for volume is length × width × height. The sample box has the area of 23 1/3 which is found by length x width. They give you the height 1 1/4. I am assuming you will need to multiply 23 1/3 by 1 1/4. You'll get 350/12.

If it's simplify further it will be 175/6 or 29 1/6 as a mixed fraction.

7 0
2 years ago
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