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Nostrana [21]
3 years ago
8

Calculate the present value of the annuity. (Round your answer to the nearest cent.)

Mathematics
1 answer:
timama [110]3 years ago
6 0

Answer:

Ans. the present value of $1,300/month, at 6.4% compounded monthly for 360 months (30 years) is $207,831.77

Step-by-step explanation:

Hi, first, we have to turn that 6.4% compound monthly rate into an effective rate, one that meets the units of the payment, in our case, effective monthly, that is:

r(EffectiveMonthly)=\frac{r(CompMonthly)}{12} =\frac{0.063}{12} =0.005333

Therefore, our effective monthly rate is 0.5333%, and clearly the time of the investment is 30 years*12months=360 months.

Now, we need to use the following formula.

Present Value=\frac{A((1+r)^{n}-1) }{r(1+r)^{n} }

Everything should look like this.

Present Value=\frac{1,300((1+0.005333)^{360}-1) }{0.005333(1+0.005333)^{360} }

Therefore

PresentValue=207,831.77

Best of luck.

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A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?
Travka [436]

Answer:

area=\frac{85}{4}feet^{2}

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

perimeter=18\frac{1}{2}\\\\length=5

2(length+width)=perimeter

Substitute,

2(5+width)=18\frac{1}{2}

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

2(5+width)=\frac{37}{2}

Inverse operations,

2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

length=5\\\\width = \frac{17}{4}

length*width=area

Substitute,

5*\frac{17}{4}\\\\=\frac{85}{4}

area=\frac{85}{4}feet^{2}

4 0
3 years ago
A rectangle has a length that is 10 less than 3 times the width. If the rectangle has an area of 8 square feet, what is the widt
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Solve this problem by forming an equation

3x - 10 = 8

3x = 18

The width of the rectangle is 6 square feet.

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Answer:

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