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2 years ago

Help me plsssss I am failing in this class pls give me step by step

Mathematics

2 answers:

Elenna [48]2 years ago

8 0

Answer: I think it’s “y=3x-4”

Contact me if it’s the right answer. If not, I’m sorry. Hope for the best.

Step-by-step explanation:

Vinvika [58]2 years ago

5 0

Y=-3x+2 bc the line is going down so it’s negative and the y intercept is 2

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A school has an equal amount of boys and girls. You use a coin to simulate the first three students to arrive at school each day

Nimfa-mama [501]

Answer:3/20

Step-by-step explanation:

Heads=Boy

Tails=Girl

If the first 3 students are boys, all 3 coins must be heads.

Because in 3 of these experiments, the coins all land on heads, and there are 20 experiments completed, 3 out of the 20 experiments are 3 boys; 3/20.

3 0

2 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

a silkworm winds its cocoon out of one long silk fiber. to make silk thread, 3 to 10 of these silk fibers are unwound from their

Scorpion4ik [409]

Answer:

Possible lengths of the silk fibre 'x' are 100, 75, 60, 50 and 30 yards respectively.

Step-by-step explanation:

Let the length of the silk fiber = x yards.

Let the number of silk fibres = a.

It is given that the silk fibers between 3 to 10 yards are combined to form a silk thread of 300 yards.

So, we get the equation,

$ax=300$ , where $3\leq a\leq 10$

i.e. $x=\frac{300}{a}$ , $3\leq a\leq 10$

So, the possible values of 'a' are 3, 4, 5, 6 an 10.

Thus, the possible lengths of the silk fibre 'x' are 100, 75, 60, 50 and 30 yards respectively.

3 0

2 years ago

Can you PLEASE show this on a graph?

kodGreya [7K]

Answer:

May or may not be right, your welcome.

Step-by-step explanation:

Rise/Run.

Plot 1.

Go down 2.

Go to the right 3, plot.

6 0

3 years ago

What is the value of x if AP and BP are tangent segments <br> AP = 10x - 15 and BP = 7x + 3

worty [1.4K]

If AP and BP are tangent segments connected outside of the circle at point "P" then <span>AP = BP so,
10x - 15 = 7x + 3</span>
3x = 18
x = 6

8 0

3 years ago