A school is organising a competition. There are 128 students from the Maths specialist class and 80 students from the English sp
1 answer:
Answer:
5 english students in each team
Step-by-step explanation:
So there are multiple ways to do this, you could do trial and error or you could factor out common numbers between the two.
Through trial and error, the lowest possible number of groups that could be divided between the number of students whilst still being able to maintain a whole # was 16 groups
- 128 math students ÷16 groups = 8 math students/group
- 80 english students ÷ 16 groups = 5 english students/group
The other way to solve this is to factor out common numbers between the two:
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In the given diagram, the measure of ∠3 will be 105°.
In the given diagram, ∠3 and ∠6 are consecutive interior angles.
<h3>How to form supplementary angles by transversal?</h3>If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles formed are supplementary.
That is,
∠3 + ∠6 = 180°
From the given information,
∠6 = 75°
Then,
∠3 + 75° = 180°
∠3 = 180° - 75°
∠3 = 105°
Hence, the measure of ∠3 will be 105°.
Learn more about the measures of angles here: brainly.com/question/2883630
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Step-by-step explanation:
See whenever we have two variables like x and y.
And also we have given two equations in terms of x and y.
Example: ax + by = p and cx + dy = q
In order to get the solution, we need to find the value of x and y using the given two equations.
So here what we can do is:
Consider any one equation and get x or y from that equation.
i.e consider ax + by = p or x =
Now plug value of x (or y) from the equation you have considered into the another equation.
i.e c()+dy = q
Now solve this equation to get y (or x).
and after that we can find the other variable.