A school is organising a competition. There are 128 students from the Maths specialist class and 80 students from the English sp
1 answer:
Answer:
5 english students in each team
Step-by-step explanation:
So there are multiple ways to do this, you could do trial and error or you could factor out common numbers between the two.
Through trial and error, the lowest possible number of groups that could be divided between the number of students whilst still being able to maintain a whole # was 16 groups
- 128 math students ÷16 groups = 8 math students/group
- 80 english students ÷ 16 groups = 5 english students/group
The other way to solve this is to factor out common numbers between the two:
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Answer:
Step-by-step explanation:
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2. Divide both sides by -2. Notice that the direction of the symbol of the inequality will change. Then:
3. Add 22 to both sides. Then:
4. Divide both sides by -7. Notice that the direction of the symbol of the inequality will change. Then:
5. Subtract 30 from both sides. Then:
6. Divide both sides by -5. Notice that the direction of the symbol of the inequality will change. Then:
7. Subtract 13 from both sides. Then:
8. Add 12 to both sides. Then: