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4 years ago

Complete the square and identify the vertex of y=x^2-8x+3

Mathematics

1 answer:

topjm [15]4 years ago

6 0

Answer:

yes because someday we meet your husband

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How much is a milliliter

Sphinxa [80]

-- 236 of them make 1 cup
-- 946 of them make 1 quart
-- the volume of a tiny cube that's 1 centimeter along each edge
-- 16.4 of them in a little cube that's 1 inch along
-- 4.9 of them make a standard cooking teaspoon
-- a perfume that cost $50 an ounce would cost $1.69 per milliliter

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4 years ago

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Find an equation of the line passing through the point (-1,8) and parallel to the line joining the points (-3,4) (4,-1).

bulgar [2K]

Answer:

The equation of the line will be $7y=(-5x)+51$

Step-by-step explanation:

If a line passes through two points (x,y) and (x',y') then slope of the line will be = $\frac{y-y'}{x-x'}$

Now we know the points are (-3,4) and (4,-1) then the slope of the line will be = $\frac{4-(-1)}{(-3-4)}$ = $\frac{5}{(-7)} =(-\frac{5}{7}$ )

We know that two parallel lines have the same slope then a line which is passing through a point (-1,8)will be =( $-\frac{5}{7}$ )

Let the equation of the line is y=mx+c

Then by putting the value of x,y and m we can get the value of c.

$8=(-\frac{5}{7})+c$

$c=8-\frac{5}{7} \\c=\frac{56-5}{7} =\frac{51}{7}$

Then equation will be $y=(-\frac{5}{7})x+\frac{51}{7}$

$7y=(-5x)+51$

5 0

4 years ago

How do you turn 0.8 into a fraction

krok68 [10]

8/10, 80/100/ 16/20 so on and so on

3 0

3 years ago

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A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

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3 years ago

How could you get a "A" on a math test

AlexFokin [52]

Answer:

by using brainly :)

Step-by-step explanation:

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4 years ago

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