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Aleksandr-060686 [28]
4 years ago
12

Find an equation of the line passing through the point (-1,8) and parallel to the line joining the points (-3,4) (4,-1).

Mathematics
1 answer:
bulgar [2K]4 years ago
5 0

Answer:

The equation of the line will be 7y=(-5x)+51

Step-by-step explanation:

If a line passes through two points (x,y) and (x',y') then slope of the line will be = \frac{y-y'}{x-x'}

Now we know the points are (-3,4) and (4,-1) then the slope of the line will be =\frac{4-(-1)}{(-3-4)}=\frac{5}{(-7)} =(-\frac{5}{7})

We know that two parallel lines have the same slope then a line which is passing through a point (-1,8)will be =( -\frac{5}{7})

Let the equation of the line is y=mx+c

Then by putting the value of x,y and m we can get the value of c.

8=(-\frac{5}{7})+c

c=8-\frac{5}{7} \\c=\frac{56-5}{7} =\frac{51}{7}

Then equation will be y=(-\frac{5}{7})x+\frac{51}{7}

7y=(-5x)+51


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25x25 in exponential form
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25 to the 2 or 25^2

Explanation:
There are 2 25’s 25x25, so the amount of exponents is the same as the number of repeated numbers
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2 years ago
I need to get 2 answered please help it’s with mean, median and mode
Marat540 [252]
They are all averages

mean=average 4+6=10, 10 divded by 2= 5, the mean is 5

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7 0
3 years ago
(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

(c) y'' + 2y = −8x + 14

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

8 0
3 years ago
Please help! (Pythagorean theorem stuff)
vova2212 [387]

Answer:

Pretty sure its 6

Step-by-step explanation:

The hypotenuse is double the length of the shortest side

4 0
2 years ago
What is the relationship between the 1s in 911,147,835
lukranit [14]
Find the relationship of 1’s in the given number.
given number = 911 147 835
before we are going to determine the relationship of 1’s , let’s give each digit’s place value.
9 hundred million
1 ten million
1 million
1 hundred thousand
4 ten thousands
7 thousands 
8 hundreds
3 – tens 
5 - ones
Now, we have the 1 ten million, 1 million, and 1 hundred thousand
What is the relationship of the 3.
=> we’ll those 1’s are 10 times greater with each other
=> 1 million is 10 times greater than 1 hundred thousands
=> 100 000 x 10 = 1 000 000
=> 1 ten million is ten times greater than 1 million
=> 1 000 000 x 10 = 10 000 000
3 0
3 years ago
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