Order from least to greatest: ‐7, 9, 0, 33, ‐56, 78, ‐1

Two paths each of width 4m run across the middle of a rectangular field 24m long and 16m wide. Calculate the area of the paths.

djverab [1.8K]

Answer:

272cm2

Step-by-step explanation:

4m×2=8

width ×long=area

8m×24m=272cm2

7 0

3 years ago

What is the value of x?

Ksenya-84 [330]

Step-by-step explanation:

$\frac{360 - 2(x + 30)}{2} = x \\ 360 - 2x - 60 = 2x \\ 300 - 4x = 0 \\ 4x = 300 \\ x = 300 \div 4 = 75$

4 0

3 years ago

Read 2 more answers

1 Point

I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

7 0

3 years ago

The test statistic of z=2.08 is obtained when testing the claim that p≠0.611. a. Identify the hypothesis test as being two-tail

krek1111 [17]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

When the two-tailed were testing then:

Null and alternative hypothesis:

$H_0 : p = 0.611\\\\H_a : p \neq 0.611$

Testing the statistics:

$\to z = 2.08\\\\P-value = 0.0375\\\\\alpha = 0.01\\\\0.0375> 0.01\\\\P-value < \alpha\\\\$

therefore, it fails to reject the null hypothesis.

8 0

3 years ago

Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8.

Gala2k [10]

Vertex is directly in middle of directix and focus

distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice

it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2

5 0

3 years ago