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4 years ago

Pleasee helpp 5 to 10 asap need it for a test

Mathematics

1 answer:

zhannawk [14.2K]4 years ago

6 0

Answer:

5.)C 6.)A 7.)D 8.)D 9.)A 10.)B

Step-by-step explanation:

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Find the volume of each figure round to the near tenth only number 2 pls it’s 20 points

Nana76 [90]

Answer:

2094.4yds cubed

Step-by-step explanation:

V=pi*r^2*h/3

V=pi*100*20/3

V≈2094.4

6 0

3 years ago

How do you get the answer for 7 5/6 + 2 3/6

Blizzard [7]

First you would add 5/6 and 3/6 which would be 8/6. Next you would convert the improper fraction (8/6) into a mixed number which would be 1 2/6. Now just add 7 and 2 which is 9. Finally you would add the whole number and the mixed number. So your answer is 10 2/6 unless the instructions say to simplify then your answer would be 10 1/3.

3 0

3 years ago

Read 2 more answers

01.01 LC)Which number line best shows how to solve −2 − ( −6)?

liraira [26]

Answer:

-6 - (-8) = 2.

Your number line might have a bubble at 2. Or it may show movement 8 units to the right of -6. Whatever it is, you should end up at the value of 2.

Step-by-step explanation:

4 0

4 years ago

12.

pashok25 [27]

<span>Last year, the average math SAT score for students at one school was 475. The headmaster then introduced a new teaching method hoping to improve scores. This year, the mean math SAT score for a sample of students was 491. The headmaster concluded that the new teaching method produces higher SAT scores. The problem with reporting results this way is voluntary response. The information of how the teaching method isnot mentioned.</span>

8 0

4 years ago

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago