<u>Question: Solve the inequality 10(z + 3) ≥ 10z + 19.</u>
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<em>Answer:</em> <em>The answer to your question is "All Real Numbers". Please see the attachment below for all the steps provided. Since 0≥-11, this means that, "All Real Numbers; [Numbers greater or equal to 1] are going to be greater than -11. Thus, meaning that the answer is </em><em>All Real Numbers.</em>
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Answer:
(6,2) y-coordinate is 2
Step-by-step explanation:
Answer:
Length and the width of the rectangle is 15.5 inches and 8.5 inches respectively.
Step-by-step explanation:
Given:
Length = 7 inches + Width
=> P = 48 inches
=> L = (7 + W) inches............. (1)
Perimeter 'P' is the sum of all sides of the rectangle 2 (L + W)
∴ 48 inches = 2 (L + W) .................(2)
Substitute for L in equation (2)
∴ 48 inches = 2 [(7 + W) + W]
48 = 2[7 + 2W]
48 = 14 +4W
48 - 14 = 4W
34 = 4W
W = 8.5 inches
Recall that: Length, L = (7 + W)
∴ L = (7 + 8.5)
L = 15.5 inches
Expand the expression as
(<em>s</em> + 1)³/<em>s</em> ⁵ = (<em>s</em> ³ + 3<em>s</em> ² + 3<em>s</em> + 1)/<em>s</em> ⁵
… = 1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵
Then taking the inverse transform, you get
LT⁻¹ [1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵]
… = LT⁻¹ [1/<em>s</em> ²] + LT⁻¹ [3/<em>s</em> ³] + LT⁻¹ [3/<em>s</em> ⁴] + LT⁻¹ [1/<em>s</em> ⁵]
… = LT⁻¹ [1!/<em>s</em> ²] + 3/2 LT⁻¹ [2!/<em>s</em> ³] + 1/2 LT⁻¹ [3!/<em>s</em> ⁴] + 1/24 LT⁻¹ [4!/<em>s</em> ⁵]
… = <em>t</em> + 3/2 <em>t</em> ² + 1/2 <em>t</em> ³ + 1/24 <em>t</em> ⁴
