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Kazeer [188]
3 years ago
14

The table shows several points for function h(x). A 2-column table with 6 rows. Column 1 is labeled x with entries 0, 3, 6, 9, 1

2, 15. Column 2 is labeled h (X) with entries 1, 6, 12, 2, 8, 9. Which point is on the graph of the inverse function h–1(x)?
Mathematics
1 answer:
irinina [24]3 years ago
7 0

Answer:

help me ok  help me help me help me help

Step-by-step explanation:

Examine this algebraic expression:

3x

4

− 2y +

3

7

What are the variables?

What are the coefficients?

What is the constant?

Explanation:

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SashulF [63]
C. X= 7 only


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3 years ago
Can yall help plz.........................
vampirchik [111]

Answer:

6^-8 or 1/ 6^8

Step-by-step explanation:

When there is a fraction with the same base, then subtract the exponent of the denominator from the exponent of the numerator.

6^-3 / 6^5 = 6^(-3-5) = 6^-8

7 0
4 years ago
Convert 21/40 to a percent
Naya [18.7K]
21/40 = 52.50% (52.5)
5 0
4 years ago
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City planners are planning to build a new community park. They agree that the park will be rectangular in shape, but the propose
podryga [215]

Answer:

  (c)  714.96 = 21.6(w +4.7)

Step-by-step explanation:

The area of the rectangular park will be the product of its length and width. This relation is used to write an equation to find the original width of the park.

<h3>Width</h3>

Let w represent the original width of the park in meters. The new width is 4.7 meters more, so is represented by (w +4.7).

<h3>Other dimensions</h3>

The length of the park is given as 21.6 meters. The area is given as 714.96 square meters.

<h3>Area formula</h3>

The various dimensions of the park are related by the area formula:

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4 0
2 years ago
Solve the equation 6w2 – 7w – 20 = 0.
azamat

For this case we have the following quadratic equation:

6w ^ 2-7w-20 = 0

Where:

a = 6\\b = -7\\c = -20

Its roots will be given by:

w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}

The roots are:

w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}

Answer:

w_ {1} = \frac {5} {2}\\w_ {2} = - \frac {4} {3}

7 0
3 years ago
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