Substitute x with the members of the domain.
f(x) = 5x² + 4
Substitute with the domain of -4
f(x) = 5x² + 4
f(-4) = 5(-4)² + 4
f(-4) = 5(16) + 4
f(-4) = 80 + 4
f(-4) = 84
Substitute with the domain of -2
f(x) = 5x² + 4
f(-2) = 5(-2)² + 4
f(-2) = 5(4) + 4
f(-2) = 20 + 4
f(-2) = 24
Substitute with the domain of 0
f(x) = 5x² + 4
f(0) = 5(0)² + 4
f(0) = 5(0) + 4
f(0) = 0 + 4
f(0) = 4
Substitute with the domain of 1.5
f(x) = 5x² + 4
f(1.5) = 5(1.5)² + 4
f(1.5) = 5(2.25) + 4
f(1.5) = 11.25 + 4
f(1.5) = 15.25
Substitute with the domain of 4
f(x) = 5x² + 4
f(4) = 5(4)² + 4
f(4) = 5(16) + 4
f(4) = 80 + 4
f(4) = 84
The range of the function for those domain is {4, 24, 15.25, 84}
Answer:
The number w is 4,000
Step-by-step explanation:
Let
w ------> the number
we know that
36 is 0.9% of number w
w represent the 100%
so
using proportion
Find out the number w
therefore
The number w is 4,000
Well you can graph it by plotting 3 points then drawing a line through these 3 points. The graph will be a straight line . By plotting 3 points you can be more sure if you are right, because if you make a mistake then they might not make a straight line.
Put y = 0 in the equation and find the x coordinate:-
x + 5(0) = -20
x = -20
So we have one point to plot:- (-20,0)
Putting x = 0 we get 5y = -20 so y = -4
Second point:- (0, -4)
Putting x = 5 say we get 4 + 5y = -20 so y = -25/5 = -5
so our 3rd point is (5, -5)
Answer:
<u>greater risk of a Type I error and a lower risk of a Type II error </u>
Step-by-step explanation:
<em>Remember</em>, in statistics, alpha (or the significance level) α, refers to the probability of rejecting the null hypothesis when it is true.
Hence, setting alpha at 0.05 (or 5%) instead of 0.01 (or 1%) implies that the researcher is increasing how far away the statistics data needs to be from the null hypothesis value before they can decide to reject the null hypothesis. In other words, a probability of 5% is greater than 1%, resulting in a greater risk of a Type I error and a lower risk of a Type II error.
