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Sidana [21]
3 years ago
8

In glycolysis, pyruvate, ATP, and NADH are produced. The lactic acid fermentation process uses the NADH molecule from glycolysis

to convert pyruvate into lactate. During lactic acid fermentation, the NADH molecule transfers electrons to the pyruvate molecule and is converted to NAD+. How do you think this transfer of electrons helps the lactic acid fermentation process repeat itself? will give brainliest
Biology
1 answer:
jekas [21]3 years ago
8 0

Answer:

Explanation:

<em>Fermentation does not involve an electron transport system, and no ATP is made by the fermentation process directly. Fermenters make very little ATP—only two ATP molecules per glucose molecule during glycolysis. ... During lactic acid fermentation, pyruvate accepts electrons from NADH and is reduced to lactic acid.</em>

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Use the information from Parts B and C to solve this problem. If a rabbit of genotype AaBb is bred to a rabbit of genotype AaBb,
Kipish [7]

The question is incomplete and the complete question is

Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.

Answer:

AABb or AaBB

Explanation:

We know that,

aabb genotype - 6 cm

AABB genotype- 16-cm

To calculate the length of earlobe contributed by each allele in a genotype is :

1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)

2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)

Now to have the earlobe to be 13.5 cm long then the genotype must be

13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B

Therefore, the genotype will be-either AABb or AaBB

3 0
3 years ago
Identify the labeled structures. A B C D E
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Answer:

A is cell wall

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A is ribosome

D is nucleus

3 0
3 years ago
What is the important of water​
crimeas [40]

Answer:

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EXPLAINATION:

Hope it helps. Please mark me as the brainliest.

3 0
3 years ago
Which is an agent that caused a mutation in DNA and chromosomes?
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8 0
3 years ago
Read 2 more answers
Suppose that in unicorns, two autosomal loci interact to determine the type of tail. One locus controls whether a tail is presen
Nina [5.8K]

Explanation:

As you can see in the picture below, this is a dihybrid cross with a twist.

We can accomplish that mutually parentages are heterozygotes for both characters because the genotypes are  

9 unicorns with curly tails (shown in green)

3 with straight tails (shown in red)

3  curly tales trait carriers with no tail (shown in dark blue)

1  straight tail trait carriers with no tail ( shown in light blue)

If this was an ordinary case of the dihybrid cross, we would get a 9:3:3:1 phenotype ratio.

However, since the first trait, the presence of the tail, is affecting the other trait, the trait texture, the ratio is altered.

\frac{1}{4} of the offspring (genotypes tt C_   and tt SS) has no tail, therefore we cannot observe the texture of the tail (some of the tailless individuals have Curly alleles -blue squares marked with green, some of them have Straight alleles -blue square marked with red ).

Therefore, the altered ratio is  \frac{1}{2} curly tails,\frac{1}{4} straight tales, \frac{1}{4} tailless

6 0
2 years ago
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