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Elden [556K]
3 years ago
10

Does anyone have any Idea how to solve this?

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0

Answer:

x = 12

Step-by-step explanation:

Remark

These two angles are corresponding angles and as such, they are equal.

Equation

8x+ 36 = 5x + 72

Solution

Subtract 5x from both sides

8x - 5x + 36 = 5x - 5x + 72          Combine like terms.

3x + 36 = 72                                 Subtract 36 from both sides

3x + 36 - 36 = 72 - 36                  Collect like terms

3x = 36                                          Divide by 3

3x/3 = 36/3                                   Divide

x = 12                                             Answer

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Data is collected to perform the following the hypothesis test:
nekit [7.7K]

Answer:

option f is right

Step-by-step explanation:

Given that data is collected to perform the following hypothesis test.

H_0: \mu = 5.5\\H_a: \mu >5.5

(right tailed test)

Sample mean = 5.4

p value = 0.1034

when p value = 0.1034 we normally accept null hypothesis.  i.e chances of null hypothesis true is  the probability of obtaining test results at least as extreme as the results actually observed during the test, assuming that the null hypothesis is correct

f) If the mean µ does not differ significantly from 5.5 (that is, if the null hypothesis is true), then the probability of obtaining a sample mean y as far or farther from 5.5 than 5.4 is .1034.

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5 0
3 years ago
Describe the process you would use to find the solution to the problem 3 1/4 1 1/3− . Express your answer numerically and with a
oksian1 [2.3K]
3 1/4-11/3
31/4 simplifies to 13/4
So you now have 13/4-11/3
Which is -5/12
your final answer is -5/12
7 0
3 years ago
Brian received a gift card of $60 for a pizza restaurant. The restaurant charges $5 per pizza. Ashley received a gift card of $1
Semmy [17]
Ashley can purchase 10 pizzas and Brian can purchase 12 so there would be nothing left on the cards

5/60=12

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4 0
3 years ago
Using a proportion, what can you infer about the number of households in her town that have more than three children?
eduard

Answer:

About 296 households have more than three children.

Step-by-step explanation:

The complete question is:

Carmen used a random number generator to simulate a survey of how many children live in the households in her town. There are 1,346 unique addresses in her town with numbers ranging from zero to five children. The results of 50 randomly generated households are shown below. Children in 50 Households Number of Children Number of Households 0 5 1 11 2 13 3 10 4 9 5 2 Using a proportion, what can you infer about the number of households in her town that have more than three children? About 242 households have more than three children. About 269 households have more than three children. About 296 households have more than three children. About 565 households have more than three children.

Solution:

The data provided for the number of children and number of households is:

Number of Children (<em>X</em>)          Number of Households (<em>f</em> (X))

               0                                                   5

               1                                                    11

               2                                                   13

               3                                                   10

               4                                                    9

               5                                                    2

           TOTAL                                             50

Compute the probability of households having more than three children as follows:

P (More than 3 children) = P (4 children) + P (5 children)

                                        =\frac{9}{50}+\frac{2}{50}

                                        =\frac{11}{50}

                                        =0.22

Let the random variable <em>Y</em> be defined as the number of households having more than three children.

The probability of the random variable <em>Y </em>is, <em>p</em> = 0.22.

The entire population, i.e. total number of addresses in Carmen's town with numbers ranging from zero to five children, consists of <em>N</em> = 1,346 households.

Compute the expected number of households having more than three children as follows:

E(Y) =N\times p

         =1346\times 0.22\\=296.12\\\approx 296

Thus, about 296 households have more than three children.

4 0
3 years ago
G(x) = 4x + 4<br> F(x)=3/5x - 9/5
Wittaler [7]

Answer:

need more info

Step-by-step explanation:

7 0
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