Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
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10 ball bearings is the correct answer, i hope it works
For one semester a School A-
750 + 200 = 950
For one semester at School B-
10 percent off of 1,000 is 900
School A- $950
School B- $900
Answer:
Deon spent 1/10 of an hour more on chemistry than on math
Step-by-step explanation: